#dfm on a mad one
11 messages · Page 1 of 1 (latest)
so:
4 days in total
day 1:
60 minutes - s=vt, v=s/t - so v=1/t, where t is an integer
day 2 - 4:
v=1/t+5
v=1/t+10
v=1/t+15
distance is also an integer
hm
Im fairly certain this is how you do it
Say the speeds of the four days are a,b,c and d
let one mile = x, and the time be in minutes
a = x/t
b = x/(t+5)
c = x/(t+10)
d = x/(t+15)
total distance over four days is 60(a + b + c + d)
= 60x/t + 60x/(t+5) + 60x/(t+10) + 60x/(t+15)
All of these different distances are integers, so
t|60
t + 5|60
t + 10|60
t + 15|60
x is just one, so it divides 60 and 60x for clarification
Factors of 60 are 1,2,3,4,5,6,10,12,15,20,30
Since all of the above divide it, we get that t has to be 5 for this to work, since 5, 10, 15 and 20 all divide 60
And then with t as 5, we get total distance as 25 miles
oh my days tysm!!!!
just a quick question why did you do 60(a+b+c+d) like how did you know how to do that
D = s*t
Time is 60 minutes, speed is the different speeds
I just wrote 60(a+b+c+d) bc it was quicker to type than 60a + 60b + 60c + 60d
And each 60 * speed was the distance travelled on each respective day
A day 1, b day 2, c day 3 and d day 4
okay im glad I was on the right lines