#dfm on a mad one

11 messages · Page 1 of 1 (latest)

keen sand
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this question makes no sense even gauth maths gave an answer that isnt one of the options

this is for the guy im tutoring btw not me

spiral grail
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so:
4 days in total

day 1:
60 minutes - s=vt, v=s/t - so v=1/t, where t is an integer

day 2 - 4:
v=1/t+5
v=1/t+10
v=1/t+15
distance is also an integer

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hm

brisk hatch
# keen sand this question makes no sense even gauth maths gave an answer that isnt one of th...

Im fairly certain this is how you do it
Say the speeds of the four days are a,b,c and d
let one mile = x, and the time be in minutes
a = x/t
b = x/(t+5)
c = x/(t+10)
d = x/(t+15)

total distance over four days is 60(a + b + c + d)
= 60x/t + 60x/(t+5) + 60x/(t+10) + 60x/(t+15)
All of these different distances are integers, so
t|60
t + 5|60
t + 10|60
t + 15|60
x is just one, so it divides 60 and 60x for clarification
Factors of 60 are 1,2,3,4,5,6,10,12,15,20,30
Since all of the above divide it, we get that t has to be 5 for this to work, since 5, 10, 15 and 20 all divide 60
And then with t as 5, we get total distance as 25 miles

keen sand
brisk hatch
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D = s*t

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Time is 60 minutes, speed is the different speeds

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I just wrote 60(a+b+c+d) bc it was quicker to type than 60a + 60b + 60c + 60d

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And each 60 * speed was the distance travelled on each respective day

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A day 1, b day 2, c day 3 and d day 4

spiral grail
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okay im glad I was on the right lines