Not sure how to do this question in mechanics as level

[wet snow]

are you given a value for the height from where the stone falls?

without the value it becomes a bit of a mess with square roots when you try find the value of u in terms of s

however the essence of the question is just using this equation

the time is the same from when the ball is thrown and 2secs after the stone is dropped

im assuming you ignore drag in the q too

the value of u is lowest when the ball hits the stone at the lowest possible height (so they travel the most height), so at water

so then the distance travelled by the stone is s-19.62 (you can get this since acceleration is 9.81m/s^2), and the distance travelled by the ball is s

the time is the same

so then you input these values into the equation, and then you can rearrange for u

the equation for the ball is 0.5at^2 + ut - s = 0
the equation for the stone is 0.5at^2 + 19.62t - (s - 19.62) = 0

t is the same in both equations, so change the subject for t and equal then them both,
then you can rearrange for u, a being 9.81m/s^2 for both

[rigid palm]

oh wow thank you i didn’t see this

[rigid palm]

ah i forgot i think it was like 130

[rigid palm]

thank you, btw maths a level you consider gravity as 9.8 instead of 9.81, 9.81 is physics

just wanted to let you know in case you do maths a level coz you’ll lose marks