#normal distribution b & c
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aii) p(x>=15) = p
1-p=q
conside pp+pq+qp
for b im not too sure sorry
i need help on c as well ๐ญ i did the part i circled, i dont get how to get the values
wdym?
for them to revcieve a compensation the delay must exceed 15 mins so x>15 for at least one of the journeys
they do 2 trips so both can be delayed more than 15 or only 1
it says it has 2 delayed trains
i tried squaring part a but the ms did sm other stuff
idk what they ddi
yh thats why i said 2 trips
as in 2 trips on a train
yeah
but idk how to only get 1 refund from that ๐ญ
surely if train is delayed twice you should get 2 refunds
it says at least 1 refund
that means they could get 1 or 2
so how would you work it out?
either 1 - p(x<15)^2
or do this #
cause that comse from refund refund or refund no refund or no feund refund
ohh i kinda get it
wait what does the 1-p represent?
1-p = q = p(x<15)
ohh so no refund
c is basically a fancy hypothesis test
normal distribution b & c
you set it up normally
i dont get how to find the values
i did the things i circled
i dont know how to do the last 2 steps
find a value for c that will be the closest to 0.005
oh what the
yeah omg
i thought i did that before ๐ญ oops
if it was binomial would i just guess?
yeah, there's no inverse normal for binomial
oh okay
that's why in binomial the critical regions are never decimals
yeahh
do u know how to do b?
i dont know why they did it like this
i thought i wouldve had to use inverse normal
it didnt say given that
how was i supposed to recognise?
and for a reason I can't remember, when you do given that in these types of questions, you've only gotta consider one of them
wdym?
look in the ms
it should be
(P(X>m) n P(X>15))
/P(X>15)
but it's just the m
I think you have to consider the values it can take
smth like that
it's probably in my notes somewhere
yeahh cause sometimes you gotta do like p(15<x<20) for example
yeahhh
if you find them send it pls ๐ญ
will do