#AQA Further Maths Paper 2

1 messages · Page 1 of 1 (latest)

patent ledge
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What do we thinks coming up?

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@wintry meadow

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@violet dock

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@frigid smelt

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@distant cape

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i dont remember who does aqa

patent ledge
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Do you guys think more complex numbers will come up

violet dock
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yeah

patent ledge
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i hope they dont do a big question on complex numbers

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like a roots of unity one

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actaully i dont mind that but

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doyou think it will be like paper 1 where they was just loads of smaller questions

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swear there was like 18 questions

magic torrent
patent ledge
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i just couldnt remember what they are called

frigid smelt
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Cuz they are gonna make it harder

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So less questions but more marks I think

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Anyway it's gonna have like 15+ regardless, it's usually around this always

patent ledge
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maybe a little bit but not loads

frigid smelt
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It's gonna be like last year

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First paper ez

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Then the second one harder

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It won't be the same difficulty, no way

patent ledge
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yeah i still need to do 2023

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gonna do it tomorrow

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i think if theres any hard question on 2023 they will reask them in a slightly easier way

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/similar concepts

frigid smelt
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Yeah

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The tan5pi/12 ine

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Is similar to what they asked in 2023

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Basically the exact same thing

patent ledge
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ye

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i got that wrong😭

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so stupdi

frigid smelt
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Me too

patent ledge
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there was like 17 marks already on complex numbers so there might not be any on paper 2

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but since the number of questions each year seems to increase if there is like 16 questions they could be one more

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i think there will be a coupled differential equation even tho there was lots previously

patent ledge
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2 days

frigid smelt
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There's literally nothing to do for pure 😭

patent ledge
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ye

patent ledge
patent ledge
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What does ACF mean?

frigid smelt
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Any correct form

patent ledge
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2023 paper 2 was quite hard

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like time wise

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there was a few questions where you could go down different roots

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and it would mean they would take ages

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like the 3 marker at the start

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also q14

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not that they were hard but not many marks

frigid smelt
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Paper 1 or 2?

patent ledge
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2

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meant paper 2

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not 3

patent ledge
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Can someone explain how I’d find c and d?

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@distant cape

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@violet dock

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@frigid smelt

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@wintry meadow

wintry meadow
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how is the method any different to a and b

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@patent ledge

patent ledge
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well they didnt use eigen vectors

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is that the way?

silent niche
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Fundamental theorem of calculus is coming up

wintry meadow
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thats one way

patent ledge
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for a and b i just thought about it

silent niche
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Further maths people

wintry meadow
silent niche
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What’s the best way to learn proof by contradiction

patent ledge
wintry meadow
wintry meadow
patent ledge
wintry meadow
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invariant points you simply multiply by some coordinates x y z and set it equal to x y z

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as they dont change

patent ledge
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ye but what about lines and planes

wintry meadow
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for lines id probably just do eigenvectors

patent ledge
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or do they want line of invarent points?

wintry meadow
silent niche
wintry meadow
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line of invariant points can be found by doing eigenvectors

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right

patent ledge
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yeye

wintry meadow
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there is another method that i know for 2x2 but its long

patent ledge
wintry meadow
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for these u might just be able to spot it

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idk about invariant plane tho

patent ledge
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ye

wintry meadow
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ive never seen q on it

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maybe like

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oh

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u just do like

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hm

patent ledge
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reflections in like x=0 plane x=0 is invariant plane

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but like

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for c i didnt even know what the tranformation is

wintry meadow
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for plane im thinking we multiply by x y z and find some conditions for it

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that might nto work tho

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give me a sec with it and then ill know

wintry meadow
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which page is that in the book?

patent ledge
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5.2B i think

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pg164

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q13

wintry meadow
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for d id say invairant line/plane y = x

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ig cuz invariant lines in 3d without specifying the z coordinate just become planes

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like in 2d y =x is a line but in 3d its a plane

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the method i did was simply multiply the matrices by x y z and set equal to x y z

patent ledge
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ok ty

wintry meadow
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thats probably not the full way or 100% correct way

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cuz it could possibly miss solutions

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but im guessing its right cuz all numbers are 1 so no scale factors

patent ledge
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ye

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so

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would the plane x=y

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be a plane of invarent points

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of a invariant plane?

wintry meadow
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uh

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i think in this case theyre all the same

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cuz theres no scale factor

magic torrent
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So what would you do to get p and q in this case?

wintry meadow
# magic torrent

ill send sol in a sec but basically u transform some general coordinates into new coordinates and then sub those new coordinate values into the plane euqation and solve for p and q

magic torrent
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That does make sense

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But what actually is an eigenplane ?

wintry meadow
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im solving it rn

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i think i know

magic torrent
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Oh

wintry meadow
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is that edexcel q

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i know how to get p, isolveed it

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im not entirely sure abt q

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i used online calcluator to find the eignevalues cuz i couldnt be bothered and got tihs

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i think q = 6 would be answer

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do u have the answers @magic torrent

magic torrent
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It's AQA

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Sure one second

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It's from their FM book

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p = 5 and q = 6

wintry meadow
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ive never seen eigen planes before wtf

magic torrent
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In this purple book

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It's my schools textbook

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I haven't either ngl

patent ledge
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@magic torrent

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can you send working out

magic torrent
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The worked solution ?

patent ledge
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ye

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from what i understand an eigen plane can occure when you have an a repeated eigenvalue and each eigenvalue has a non parrallel eigen vector

magic torrent
patent ledge
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ty

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oh so they just guessed what the eigenvectors were

magic torrent
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That's what it seems like

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But I still don't get it tbf

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It's fine

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I can ask my teacher tmr

patent ledge
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which bit

magic torrent
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What's actually going on

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Well I understand it , it's just not sure about the eigenvectors

patent ledge
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Do you understand this

magic torrent
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How did they know whixh eigenvectors

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Lemme see

patent ledge
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oh

magic torrent
patent ledge
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well i think they just picked two non parallel vectors that are perpendicular to the normal of the plane so when you cross product them you would get the plane

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i think

magic torrent
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Hmm I see

patent ledge
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wait

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nm

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thats waffle

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so you know how you can have lines on a plane

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i think they just picked two non parallel vectors that would lie on the plane

magic torrent
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Ahh ok

patent ledge
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and you can use them to get to any point on the plane

magic torrent
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Yeahhh I get what you mean

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Thank you

patent ledge
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ye

magic torrent
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There's literally that's the only q on eigenplanes in this book

patent ledge
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yeye

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i doubt it comes up

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but if it did it would be really good because i doubt many people will have gone over it

magic torrent
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Yep

wintry meadow
wintry meadow
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were there any series qs on paper 1?

wintry meadow
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when doing centre of complex circles do we include an i?

would we write it as (3,4)
or centre 3+4i

patent ledge
wintry meadow
patent ledge
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but not 100% sure

wintry meadow
patent ledge
wintry meadow
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hm

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is it old spec book

patent ledge
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nah

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2017

wintry meadow
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textbooks do just add extra stuff tho

patent ledge
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ye

patent ledge
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Can you guys do part a?

wintry meadow
patent ledge
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nah its fine now

patent ledge
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@wintry meadow

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Try this one

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swear its impossible

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@frigid smelt

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@magic torrent

wintry meadow
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yh im struggling with that one

patent ledge
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idk how to do it

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@wintry meadow

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thats the ms

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but they subtracted aR2

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i did not know you could do that

wintry meadow
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its just like minusing row 1 a few times

patent ledge
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if a matrix is singular does that mean det M =0

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im worried for this exam cos there was 12 days i feel like theres so much little stuff iv forgotten

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well not forgotten

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but its not at the front of my head

cold scarab
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i reckon just do it @patent ledge

patent ledge
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How do I do part c

frigid smelt
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Everything on the right hand side of the y axis gets reflected

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So

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Something like this

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The reason is

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Can you see how

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When you evaluate the negative x values i.e if you were to evaluate f(-2), the y coordinate will be = f(2) so will yield the same y coordinate as the positive side of that same number, if that makes sense ? ( So f(-2)'s y coordinate is the same as f(2)'s y coordinate) and same for all other postive and negative values, so it just reflects in y axis)

patent ledge
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ahhh ok ty

wintry meadow
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have they ever asked 2 simple harmonic motion q's

silent niche
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Matrices

wintry meadow
wintry meadow
patent ledge
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nah

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they havnt

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i doubt they will

wintry meadow
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alr good

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cba to do it

patent ledge
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but maybe like a 3 marker or something

wintry meadow
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probably multiple choice if they do

patent ledge
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yeye

wintry meadow
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no way they throw another entire q

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havent gotten full marks on a single coupled de question lol

patent ledge
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😂

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they might do coupled de tho

wintry meadow
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i know

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its cuz i going fast making stupid errors

violet dock
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I want a nasty but nice roots of polynomials w

wintry meadow
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tbf i dont think theres a topic thats bad that could come up

wintry meadow
patent ledge
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numerical methods

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tellin ya

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theres gonna be a nasty one

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deriving the mid ordinate rule

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bet thats on it

modest bear
modest bear
patent ledge
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ye

wintry meadow
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You can't really even derive it, it's kinda just look at the graph and make rectangles

hollow crow
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hey guys

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how hard is a level further maths

patent ledge
wintry meadow
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Anyone done

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I got the reduction q wrong

I did cos^n-2 not cos^n-1 lol

distant cape
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Harder then the first one

wintry meadow
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Yh defo

distant cape
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What did u lot get for modulus of z with the smallest argument

wintry meadow
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4 sqrt 3

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I can't remember many qs

shy moss
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that paper was not bad tbh

wintry meadow
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The DE question my values for everything were horrible

shy moss
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the complex number one was a bit ass tho

wintry meadow
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Which

shy moss
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the smallest argument thing

wintry meadow
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that was not nice

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I did some way but it wasted so much time

distant cape
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At first I thought it wanted minimum value so I wasted a bunch of time on the complex argand diagram one

distant cape
frigid smelt
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Beauty of a paper

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Made up for my uselessness on paper 1 hopefully

frigid smelt
wintry meadow
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Idk if I got that right 1

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I got 0.6 for something tho

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And 21/9

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Can't remember

shy moss
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i also struggled on the revolution about the y axis

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its int x^2 dy right

frigid smelt
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And lambda for the e^5x one was

wintry meadow
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I'll probably lose a mark or 2 for that

frigid smelt
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I don't remember but ye

shy moss
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do you not have to rearrange for x or something

frigid smelt
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I made the diff equation and skipped the rest

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Didn't have the tjme

wintry meadow
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Ye u rearrange for c

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X

shy moss
wintry meadow
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And then use the y values for the bound

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It was 0 to 5/3 for y values

shy moss
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yeah

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oh well maybe ill get a mark for the limits

wintry meadow
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I couldn't do the method of difference q

shy moss
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oh YEAH

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i forgot about that

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that was so horrible

wintry meadow
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H1ow did u do it

shy moss
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i literally tried every number in the calculator for the second part

shy moss
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i spent the time on other questions

wintry meadow
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Dis u do 3 partial fractions or 2

shy moss
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3

shy moss
wintry meadow
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Idk

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What was it

1/r(r-1)(r+1)

shy moss
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yeah

wintry meadow
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It was 0.24999

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71 gives you just 0.2499

shy moss
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thats for each term

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it asked for the first number where the sum gave that

wintry meadow
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Yh ik

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Try it there

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Maybe I put it in wrong

shy moss
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cus on my calc it gave it higher

patent ledge
distant cape
wintry meadow
patent ledge
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Did you guys answer everything

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To many questions

shy moss
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i misread the number of 9s loool

wintry meadow
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20 was so many lol

violet dock
wintry meadow
violet dock
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I’m glad people agree cos like my friends were saying it was easy

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But they slipped the complex numbers q

wintry meadow
violet dock
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Which took me AGES holy shit

violet dock
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224?

wintry meadow
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Ye I mena part a tho

violet dock
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oh yeah

shy moss
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the actual questions were easier than paper 1 imo

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but the time was a bit iffy

violet dock
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Partial fraction it

violet dock
wintry meadow
violet dock
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Yeh

wintry meadow
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I got like -1 1/2 1/2

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as valued

violet dock
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Ye same

shy moss
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yeah i got that too

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but i couldnt spot the pattern

wintry meadow
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How did u cancel the terms then?

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yh same

violet dock
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Diagonally

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U have to combine the 2 halves

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And then like

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With the whole -

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It was +1/2 +1/2 -1

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Basically

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On the diagonal

wintry meadow
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Crazy

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Was ur DE values nice or not

shy moss
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A and B were like 1/35 and 6/35

violet dock
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medium

violet dock
wintry meadow
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Nei1ther

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mine were bad

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like awfull1y bad

shy moss
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idk i put it in the calculator and it worked

wintry meadow
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Sounds right though ngl

violet dock
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I got 10/63 and 1/175 for A and B and then for the PI I got 3/2, -3/5 1/10 and -8/225

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Which my friend also got

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For the PI

wintry meadow
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That sounds right

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I didn't get that

shy moss
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your PI numbers are right

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although idk about 3/2

wintry meadow
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oh i think I put 0.6 not -0.6 which causes everything to be wrong

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lol

violet dock
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Either way method was clear

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I managed to do the complex numbers one but took me FUCKING AGES

wintry meadow
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Yh should be only 2 or 3 lost

wintry meadow
violet dock
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Part b

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Did anyone have a neat method

wintry meadow
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I did discriminant with y=mx to find coordinate

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And used distance formula

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Cuz we had distance

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Which gave x value, which gave y value

violet dock
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ye I did that as well then got tan theta

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Then put it in a triangle with that and 1

wintry meadow
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Sin?

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I did sin not tan

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Urs works

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I did sin cuz we had the hypotenuse which was the distance 4 sqrt 3 from prev part

violet dock
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ye I did that as well but didn’t wanna sub back in to find coords

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I found tan theta from gradient

wintry meadow
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Makes sense

violet dock
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Then just used a triangle and converted it to sun

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Sin**

wintry meadow
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was not a nice q

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there's probably easier method

violet dock
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Nah it took so long like it took all my checking time

wintry meadow
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I didn't check anything I think

patent ledge
violet dock
wintry meadow
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Was the person wrong about the degree 3 right

violet dock
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Yeah

patent ledge
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Also

violet dock
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Any odd degree

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It could be

wintry meadow
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I put could be 3 5 7 9 etc

violet dock
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Yeh

wintry meadow
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Yhyh

patent ledge
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Cos all the other mocks were different question lengths you aren’t used to it

violet dock
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I normally have like 1h of checking to chill

patent ledge
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Like I think question 10 I’m almost done

violet dock
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But this time omds working to the end

patent ledge
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So what do we think grade boy ada dies

wintry meadow
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I lost marks on minimum 3 qs now

violet dock
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Luckily there wasn’t an evil last q tho

patent ledge
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Boundaries

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Higher or lower

wintry meadow
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Same ish

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Paper 1 was very easy

patent ledge
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Ye

wintry meadow
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This I'd say was harder than last year

violet dock
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Yeah probs same cos p2 lower p1 higher

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My friends found this paper easy and p1 harder 😁😭😭😭

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Which was weird

wintry meadow
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fair

patent ledge
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Ye same someone else said that

wintry meadow
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like 15 qs were easy then 5 difficult

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An1yone remember mcqs

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I got 45 for 1 I think

patent ledge
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Mcqs?

wintry meadow
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At the start

patent ledge
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Oh

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Ye it was 45

wintry meadow
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I don't remember others

patent ledge
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I memorised that formula this morning

violet dock
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Yeah wA

wintry meadow
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Just gotta hope no vertical circular motion on mechanics now

patent ledge
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Ye

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I need to grind mechanics now

violet dock
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No that’s so nice

wintry meadow
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It's fine

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Depends though cuz they word it so badly

patent ledge
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The 2023 question on momentum was hard

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I’d not done one like it before

tribal heart
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I didn’t realise it was there until a minute left

wintry meadow
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Anyone know a b values for last q

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I got a is 15

tribal heart
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So I just scribbled the ibp to try get a mark 💀

frigid smelt
frigid smelt
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But it's a good question, yes

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That mech paper is hard tbf

patent ledge
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@frigid smelt did you think todays paper was harder or easier than paper 1

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Sorry

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Paper 1

frigid smelt
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Me personally, harder , but I did better on this paper than paper 1

patent ledge
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Ye

frigid smelt
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Paper 1 I just made mistakes that's why

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Stupid ones

patent ledge
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Yeye

frigid smelt
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How did you find it

patent ledge
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Ok

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Neither were hard

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But this one was more time pressure

frigid smelt
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Yeah

patent ledge
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So definitely this one

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For me

frigid smelt
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Yh 20 questions in insane bruh

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When I saw that I was like tf

patent ledge
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Ye I didn’t get the reduction question as well so sad

frigid smelt
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Part a or b?

patent ledge
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I literally practiced it for sin and tan this morning

frigid smelt
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I got a but not b

patent ledge
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Nah couldn’t prove it

wintry meadow
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I'm so mad for not getting the reduction its so easy

patent ledge
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Ye

frigid smelt
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Was it because of mistakes or ?

patent ledge
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Bluddy 9 marks

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I just couldn’t do it

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I was doing it the wrong way

wintry meadow
patent ledge
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Yeye same I think

frigid smelt
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It's -1 ye

patent ledge
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Wait

frigid smelt
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And it comes out beaituful

patent ledge
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Was it I n-2

frigid smelt
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Beautiful

wintry meadow
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no

patent ledge
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Omd

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Like

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Wait

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So was it I n = In-2

frigid smelt
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Yea

patent ledge
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Was the subscript n-2

frigid smelt
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In was on the left

patent ledge
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Yeye

frigid smelt
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And on the RHS I n-2 ye

patent ledge
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Oh ok

frigid smelt
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And n-1

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I thunk

fair echo
frigid smelt
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And this stupid calculator weren't giving me exact values for the argand diagrams one 🤣

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I had to blag it and make it equal

wintry meadow
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No eigenvectors qs

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there was like 1 vectors q over both papers too

frigid smelt
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So lucky

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I hate eigen stuff

wintry meadow
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Nah eigenvectors is so easy

frigid smelt
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Ye but not the normal ones

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The weird ones

wintry meadow
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Was the vectors q like

b × a then u do that is equal to - a x b

frigid smelt
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And also invariant planes n stuff I didn't even have time to learn so glad it didn't come up

wintry meadow
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and -c×a = a×c

frigid smelt
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But also

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Is

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E.g.

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8a × b = 8(a× b)

wintry meadow
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I got an 8 I remember

frigid smelt
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The a × b they give you, then you times it by 8?

wintry meadow
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I did

frigid smelt
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Ok good me too

wintry meadow
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idk if ur allowed

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Probably

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It makes sense

frigid smelt
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One sex

wintry meadow
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then the a×a=0

frigid smelt
frigid smelt
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Anyway it was a good paper

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I don't remember any other qs

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N the very last one

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Idk where I'm supposed to get a pi from

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Tf

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Io = 1 ?

wintry meadow
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No

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Well yes

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And then u integrate that

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To get pi/4

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and then do the formula 3 times

frigid smelt
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Ohhhhh u integrate it

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Duhhh

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Thank you

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💀💀

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I didn't integrate it

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I was thinking how am I supposed to sub jn pi/4 jnto one

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🔥🔥

violet dock
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I made an algebra mistake on the flipping maclaurin one

frigid smelt
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How did you find it nola?

violet dock
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Good very time pressured tho

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Didn’t have that much time to check so probably fucked up some algebra:numbers

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But the Qs weren’t bad

frigid smelt
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Ohh yh also

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For the Volume of revolution

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Can you just put in calc?

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Because it was only 3 marks

violet dock
frigid smelt
wintry meadow
signal acorn
#

@wintry meadow

wintry meadow
signal acorn
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What was the 10 mark diff equation

wintry meadow
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il try remember

signal acorn
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My friends are saying two things

wintry meadow
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i cant remember all

signal acorn
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So idk which one is the right q

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Was it

#

Y”+4y’-45=0

#

Forget the 0

wintry meadow
#

the solutions to the normal were 5 -9

signal acorn
#

Alright calm

wintry meadow
#

yh thats right then

signal acorn
#

And the function

#

Did it have

wintry meadow
#

the rhs had a e^5x

#

no constant

signal acorn
#

I was about to say 😭

wintry meadow
#

a x and x^2 term

signal acorn
#

People were saying e^2(x) was from the function I was so lost where they got the x from at the pi from lambda e^2x cuz the roots weren’t matching

#

But thanks for confirming

signal acorn
signal acorn
#
  • 25 x^2
wintry meadow
#

im not sure tho

#

i think it was 21e

#

actually i have no clue

signal acorn
#

Does anyone remember the function

signal acorn
wintry meadow
#

yes

#

we were given axb and axc

#

and then we told find value of

i cant remmeber numbers but eg

(3a +5b+2c)(2a)

signal acorn
#

? Something similar to this?

#

You guys are lucky man

wintry meadow
#

no

signal acorn
wintry meadow
#

it gave us values

#

for axb and axc

#

like a vector

signal acorn
#

Ohh

#

Fair enougg

wintry meadow
#

and all u had to do was notice the minus rule and like bxa = -axb etc

signal acorn
#

Yhh

wintry meadow
#

@signal acorn anoter q

using definition of maclaurin for sinx and binomial approximation give terms upto theta ^3

in

1/(1+sin(theta))^4

signal acorn
#

EASY

violet dock
violet dock
#

Might have been some other negatives the other way on the last 2 tho

wintry meadow
signal acorn
#

Damn

violet dock
#

I think

signal acorn
violet dock
#

Bc when I put it in my calc then it wasn’t close

wintry meadow
#

actually

violet dock
wintry meadow
#

yes it is 27

violet dock
#

But idk about the +- order

wintry meadow
#

thats right

#

99% sure

wintry meadow
violet dock
#

Yeah I think so too

violet dock
#

I am just so tired cos I couldn’t sleep last night

violet dock
signal acorn
#

Alr I’ll try the q now

wintry meadow
#

i dint write part of it on the last term

#

1 sec let me resend better

violet dock
#

Ohhhh I’m so stupid 😭😭😭

wintry meadow
#

wait no

#

im missing a partr

violet dock
#

Forgot the flipping x^3 term and said “didn’t need it” cos I read the expansion at first as to x^2

#

Then gave it to x^3

wintry meadow
#

its wrong anyway

signal acorn
#

Alr I got lambda as 3

violet dock
#

Ugh….

wintry meadow
signal acorn
#

I got -3/5 x^2

wintry meadow
#

sounds right

signal acorn
violet dock
wintry meadow
#

i think i put positive

violet dock
#

I think it should be 3/2

#

For e^5x

#

If I’m not mistaken

#

Then 1/10 and -8/225 or smth like that

#

Can’t remember exactly but

#

Yea

signal acorn
#

9/21 3/7

#

I got 3/7 for lambda mb

wintry meadow
#

i got 9/21 for something i think

signal acorn
#

Just divide divide properly

signal acorn
wintry meadow
#

then just simplify

violet dock
signal acorn
#

Nice easy 10 marks then

frigid smelt
frigid smelt
#

That's 0 marks surely right?

frigid smelt
wintry meadow
#

probably 1 if they got sinx maclaurin series

frigid smelt
#

And a + - 0.6

#

Idk which one

frigid smelt
#

But was way easier than last year ngl

wintry meadow
frigid smelt
#

Paper 2 last year was much harder

#

Compared to ours

wintry meadow
#

eh i think this probably harder

#

esp cuz 20 questions

modest bear
#

guys

#

how was the pape

#

paper

frigid smelt
#

Was good

#

Better than paper 1 imo

modest bear
#

damn aqa was harder than edexcel

frigid smelt
#

Huh rlly

modest bear
#

i managed to predict 90% of the topics in edexcel

#

lmao

frigid smelt
#

Nice haha

#

Have they sat paper 2 ?

#

Or just p1

modest bear
#

i knew that there was gonna be volume of revolution parametric

modest bear
frigid smelt
#

Further ?

modest bear
#

yh

frigid smelt
#

Oh I didn't even know

#

Grade boundries gonna be v high theb for edezcel it seems

#

Cuz apparently p1 was super ez too

modest bear
#

yh

frigid smelt
#

AQA too ngl

modest bear
#

we will see

patent ledge
#

65 per paper?

wintry meadow
#

Probably same as 2023 I'd guess

#

it was similar difficulty overall

patent ledge
#

ye i fucking hope its not that much higher

signal acorn
#

Was paper 2 difficult @patent ledge

frigid smelt
#

Like 75 at least

patent ledge
frigid smelt
#

Oh

#

Ye

#

Something like that

patent ledge
frigid smelt
#

You'll defo get an A

#

Regardless

signal acorn
#

Did any matrices come up like inverses

frigid smelt
#

Ye

signal acorn
#

I would say it would’ve

frigid smelt
#

It did

signal acorn
#

In terms of k?

frigid smelt
#

Yes haha

signal acorn
#

They love using the letter k

#

🤣

frigid smelt
#

So u can't check ur answer

#

👺

patent ledge
frigid smelt
#

It's all good bro

patent ledge
#

could of got an extra 9 marks

signal acorn
#

Yeah aqa always thinks of those silly ways to make people not being able to check

patent ledge
#

thats like a grade😂

signal acorn
#

NO WAY

frigid smelt
#

Last q

#

9 marks

signal acorn
#

What was it?

frigid smelt
#

cos^nx

signal acorn
#

BRO SO FREE A😭

patent ledge
#

😂

#

i literally looked at the question in the textbook and thought

signal acorn
#

Split into cos^2 and cos^n-2

frigid smelt
#

No

#

Cos^n-1x

#

And cos^x

patent ledge
#

then what pigeon?

#

?

frigid smelt
#

Then by parts

signal acorn
frigid smelt
#

With u = cos^n-1x

patent ledge
#

ye and what did you get

frigid smelt
#

And it comes out lovely

signal acorn
#

With tan u do n-2 mb

frigid smelt
#

Ye

patent ledge
#

can you do it

#

now

frigid smelt
#

Do you remember the q ?

#

The answer

signal acorn
#

Did u need to work out a definite integral?

frigid smelt
#

I can do it rough just so u can get an idea

#

One sex

signal acorn
#

Or was it just reduction formula

frigid smelt
#

Wag1 eith thjs keyboard

frigid smelt
#

Limits

#

For the second part

#

You had to do

#

I6 I think

#

And the limits were

#

0 and pi/4

#

For the whole thing ye

signal acorn
#

That’s such a nice question

frigid smelt
#

Yeah it is

signal acorn
#

Was there more calculus

frigid smelt
#

Not that I remember

#

Lucky that eigen stuff didn't come up

signal acorn
#

Any vectors?

frigid smelt
#

In terms of geometrical representation

#

Cuz I ain't got a clue

frigid smelt
#

Apart from

signal acorn
frigid smelt
#

The a × b whatever u call it

#

Crossing the different stuff

frigid smelt
signal acorn
patent ledge
#

OMD

#

im so studpid

frigid smelt
#

Nothing of eigen or diaglsationatiom

#

You forgot sinx innot

#

I bet

patent ledge
#

i differentiated cos^n-1x wrong

#

forgot to bring sin

#

fuck sake

frigid smelt
#

I knew it

#

Catches every1 out

signal acorn
frigid smelt
#

Yeah

patent ledge
#

yup

frigid smelt
#

Do you still want me to do it ?

patent ledge
#

nah its fine

frigid smelt
#

Or you shoukd be fine now?

#

Alright cool

signal acorn
#

My friend said he ain’t getting an A*

#

But he’s smart asf

#

so I don’t believe him

frigid smelt
#

I m3ssed up the inverse of the matrix I was so careful idk how

patent ledge
#

like i knew you had to bring an extra cos out but then i had n-3

signal acorn
patent ledge
#

actually sucks

signal acorn
#

U can check tho

frigid smelt
#

I can't

#

No time

signal acorn
#

As long as u have a follow up q

frigid smelt
#

Ye we did

#

That's how I knew I got it wrong

#

I got 2/3 parts correct

#

And the other didn't work out

signal acorn
#

U can just sub k=1 and u can check if the simultaneous equations work

#

Ohh

frigid smelt
#

So I messed up somewhere

signal acorn
#

I wish I was born in 2006

frigid smelt
#

You'll see the paper tomorrow right ?

signal acorn
#

Yeah hopefully 🤞🏾

frigid smelt
#

How come

#

R u a teacher ?

signal acorn
#

Nah

frigid smelt
#

Bro has connections

signal acorn
#

my friend he’s got access to something 😭

frigid smelt
#

😭😭

signal acorn
#

So he can just send me stuff 💀

frigid smelt
#

I see 😭

#

I haven't done anything for maths tmr

signal acorn
#

Nah but for aqa

frigid smelt
#

But it shoukd b fine

signal acorn
#

It’s a bit unfair for aqa

frigid smelt
#

What is

signal acorn
#

The good materials for revision are on the teachers acces thingy

#

Like look

frigid smelt
#

I've got them 😎

#

I got connections too

#

N for edexcel

signal acorn
frigid smelt
#

And OCR n stuff

signal acorn
#

Nicee

frigid smelt
#

Also exampro logins

signal acorn
#

Yeah you wouldn’t really find them elsewhere would you?

frigid smelt
#

You wouldn't

signal acorn
frigid smelt
#

I'm sure teachers give these out tho no?

signal acorn
#

Yh they do

frigid smelt
#

Not really sure why they don't give out exampro tho

#

A bit weird tbf

signal acorn
#

They gave us these for topic tests

#

For predicted grades

frigid smelt
#

Ohhh

#

Then it makes sense ig

signal acorn
#

Yh

frigid smelt
#

If the RHS of a second order was

25e^5x + ...x^2 + ..x

#

If you use

#

Axe^5x + Bx^2 + Cx

#

Is it fine

#

Without + d

wintry meadow
#

i think u need d

signal acorn
#

Nah u need that

frigid smelt
#

Oh do you

#

Ah ok

signal acorn
#

Ax^2+bx+c

frigid smelt
#

Thank you

patent ledge
signal acorn
#

Nice

violet dock
patent ledge
#

Agreed

modest bear
#

gl tomorrow

frigid smelt
#

Wait

#

Why do you need a +d

#

How are you gonna compare a constant on the left side when there is no constants on the RHS

#

So d is 0 anyway surely.. ?

#

Oh wait nvm you get more constant terms on LHS too

frigid smelt
#

Gl guys

frigid smelt
#

Easy 100%

frigid smelt
#

How did you guys find it ?

wintry meadow
#

edexcel?

frigid smelt
#

AQA

tribal heart
#

was good

patent ledge
#

When’s the fm aqa paper 2 coming

#

@signal acorn

signal acorn
#

Still don’t have the paper 😢

#

Fm is always the one they delay ffs

wintry meadow
#

U gonna do edexcel regular @signal acorn

signal acorn
patent ledge
#

What are some formulas of volumes and areas of shapes we might need to remember for mech?

wintry meadow
#

ive never seen anything thats required me to memorise shapes

#

u need to know the CoM formulas tho

#

but ig if u forget u can derive it

patent ledge
#

ye

#

thye might ask like a question that requires you to know volumes of a cone or circle

#

for some reason i always forget volume of circle and cone

#

😭

#

anyway they probably wont

#

i hope i scrapped an A in paper 2

#

because im not feeling confident about mechanics

wintry meadow
#

u said u got like 90% in paper 1

#

i thought

patent ledge
#

ye

#

i did really well paper 1

wintry meadow
#

so ur fine then

patent ledge
#

but i was so slow paper 2

#

like ik i lost 18 marks from question i ddint do

wintry meadow
#

if i didnt make any mistakes i think i could get like 90 - 95 but i wouldve so made like 80s for me hopefully

wintry meadow
patent ledge
#

ye i didnt do reduction formula

#

and

#

argan one

#

6 marker

wintry meadow
#

i doubt many people got that

patent ledge
#

and there was a 3 marker eailer

wintry meadow
#

do u do edexcel regualr or aqa

patent ledge
#

aqa

wintry meadow
#

nvm then

patent ledge
#

surly an A wont be about 65 this year

#

it was 57 last year

wintry meadow
#

u defo get an A

#

just aim for a*

#

i got no time to revise mech or stats

#

only night of physics which i cant do anything

#

gonna have to do some in morning

patent ledge
#

ye my stats is good however its so easy to lose marks

wintry meadow
#

yh

#

stats is easy

patent ledge
#

what is a conical shell

#

is it a cone

#

thats hollow

patent ledge
#

Have they ever asked us to derive the formula for integrating com

modest bear
#

@patent ledge u=2x+1

#

?

#

U^2=2x+1

#

Nvm is u=2x+1

frigid smelt
modest bear
#

@frigid smelt i got k=12

patent ledge
#

so long ago i dont remember

modest bear
patent ledge
modest bear
#

normal

modest bear
frigid smelt
modest bear
frigid smelt
#

Did you get simultaneous equations ?

modest bear
#

yes

frigid smelt
#

Oh haha

modest bear
#

i found y first

#

which was 2

#

than sub it to the other equation

#

to get 12

frigid smelt
#

Yeah ik what you done

modest bear
#

look at this nasty

frigid smelt
#

Woah

modest bear
#

had to put it into the calculator

frigid smelt
#

Yh idk what you done

modest bear
#

i made k the subject