#Trig integration
19 messages · Page 1 of 1 (latest)
What’s the full question?
Let u = tanx
du=sec^2x dx
Can u go from there and try and solve it now?
I tried doing it by trig identities but i’ll have a go at that
loks like reverse chain rule for one of the terms
so don’t see that working because you would get cosx/sec^2x
sec^2(x) tan(x)
integrates to sec(x)
if im not wrong
sec^2(x)
mb
then for the tan(x)cos(x)
it simplifies to sin(x)
okay thank you
all good
I integrated to get sec^2x then decided to do it again for some reason
cant do that cuz its not jsut that its multiplying with tan(x) too right