#idfk
90 messages · Page 1 of 1 (latest)
Why
Why tho
Wheres this question from
some next lvl predicted paper
also
i worked out the volume initally then converted to litres
and im like
depth is 6th so
6cm*
so surely its porportional
but its not
Bc the water isnt a semi circle
you can't do it because its like curved
The cintainer is
the container is that shape
thats the cross section
Bro what is this
ass question tbh
its curved so its not porportional
you gotta find out the angle at the top then find length BC using cosine
I can see a way of solving it but I don’t know if it’s the most optimal way
You can find BC using pythag
i think then u work out area of sector ACD then minus triangle ABC
but we need the angle for 1/2 ab sin(c)?
u cant assume its a right angle triangle
No if you have BC you can do 1/2 x base x height
You think the water level is just gonna curve?
ok so u do pythag thats 4 root 2
Yep
area of a sector requires the angle so dont you have to use cosine
oh wait
cant we do simple trig
Yh
Is the area of the container and water not proportional?
Sin(x) = (4 root 2 / 6)
(70.53/360) x 36pi
Subtract area of triangle
22.16
1/2 x 2 x (4 root 2) = 4 root 2
Then multiply by 2 because that’s only one side of it
Is that an exact value?
then multiply by length?
im rounding to like 2 d.p.
33*20 = 660cm^3
0.66L
let me check the ms
0.66L
1L = 1000cm^3
ok fine
Wait is that right?
its 0.66L
No I found 1 meter cubed
oh 😂
🤦♂️
That’s tough for a gcse question tho