#modelling
40 messages · Page 1 of 1 (latest)
what paper is this
2020 may
which part you need help with?
this is correct
then u use (8,50) to get another equation and solve simultaneously
idk what to do tbh
and idk how to do that
okay whag do i do after ?
find B in terms of A and e
then sub it into A + B = 94
Then you can find the value of A
And the equation of the asymptote will be y = A
if u don’t mind can i see a worked solutjon?
1 sec
appreciated
Now sub back into here
94 = A + 50e - Ae
A - Ae = 90-50e
A(1-e) = 90 - 50e
A = (90-50e)/(1-e)
Then the equation of the asymptote is y = A
I don’t have a calculator on me so you just need to type this into yours
how is y equal to A
Basically the equation is u = A + Be^-t/8
As t gets bigger and bigger the Be^-t/8 will become closer to 0
But the A will never change
So it will not go below A so the asymptote is y = A
oh i see thank you
nws
do you mind if i dm you?