#matrices fm
3 messages · Page 1 of 1 (latest)
AB = BA
A(ABA) = BA
AABAA^-1 = BAA^-1, AAB = B
AABB^-1 = BB^-1, AA = I
Therefore A² = I
3 messages · Page 1 of 1 (latest)
AB = BA
A(ABA) = BA
AABAA^-1 = BAA^-1, AAB = B
AABB^-1 = BB^-1, AA = I
Therefore A² = I