help

[cinder crane]

ik its meant to be easy i just need to know how to do this

[simple citrus]

so days needed to work is inversley proportional to hours worked

let :
d = days needed to work
h = hours worked

4 * 8 = 32

15 = k/32

32 * 15 = 480

[cinder crane]

so u find k and do the same with the values in the other bit?

[simple citrus]

d = 480/h

[simple citrus]

yup

[cinder crane]

oh shit

thx

also

[cinder crane]

i could use help with another question if u dont mind

[simple citrus]

yeah

send it

[cinder crane]

not sure what to do from here

[simple citrus]

cos 30 = rt3 / 2

12 * rt3/2 = 6rt3

tan 60 = rt3

2 * rt3 - 2rt3

6rt3 - 2rt3 = 4rt3

4rt3 = rt48

[cinder crane]

shit i used the wrong value for cos30

i used sin30

[simple citrus]

rip

[cinder crane]

how is 4rt3 = 48?

[simple citrus]

it asks for the form in rtk

so

4 = rt16

rt16*rt3 = rt48

[cinder crane]

ohh ok

[cinder crane]

any ideas on this 1

[simple citrus]

so

P(Q) = probability to qualify

P(N) = probability to not qualify

so the probability he doesnt need the 3rd jump is gonna be

0.8 + (0.2 * 0.8)

cuz he needs to either qualify on the 1st or 2nd jump

so its gonna be 0.816

i think

0.96*

[cinder crane]

what abt the tree diagram

[simple citrus]

cant do math

[simple citrus]

just fill it out

the events are independant so they will be the

same

[cinder crane]

so just

0.8 and 0.2

for it all

[simple citrus]

yup