#Alevel maths q pure yr 2
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for part a you need to re-arrange the function into y in terms of x
the actual structure is the same shape as the graph but stretched into 3 dimensions with a width in the z axis of 0.06m
volume of a general prism = area * height (or depth in this case)
the function is rearranged to y = 1/4sqrt(144-9x^2)
therefore volume = 0.06*integral from 0 to 4 of (1/4sqrt(144-9x^2))dx
therefore taking 1/4 out from the integral gives the desired result
part b is just estimating the integral
part c is dependant on where your basis points were for the estimate
I appreciate it so much thank you ๐๐
volume??