split the area into two
#integration by parts
potent dome
yes i already know that??
potent dome
no i mean to like find the co ords
i know the basics of splitting it but finding the co ords is so off putting
shrewd bane
the only co- ords you need is when the line meets the x axis so when y of the line you calculated = 0
potent dome
like how do u find this
yes i know that omg
we don't have the equation for line l
y - e = (1/1+ln x) (x-e)
potent dome
y - e = (1/1+ln x) (x-e)
but this isn't the equation though for line l
potent dome
omg yes i already know that im not fucking dumb
shrewd bane
potent dome
the point is that's not the gradient
shrewd bane
then you differentiated wrong
potent dome
the gradient is -1/2 so how are u meant to go from -1/1+lnx to -0.5
shrewd bane
the gradient is -1/2 so how are u meant to go from -1/1+lnx to -0.5
you input (e,e)
potent dome
don't even try to help me if u don't know what ur doing bye
shrewd bane
thorny thorn
Dont have to be so rude
Sub in ur x coordinate into the gradient first then find the negative reciprocal
thorny thorn
the gradient is -1/2 so how are u meant to go from -1/1+lnx to -0.5
dy/dx=lnx+1
hence the gradient of the tangent at P(e,e) is ln(e)+1 which is 2
you know that L is a normal at c
you know the normal is perpendicular to the tangent hence the gradient of the normal is the negative reciprocal of the tangent
hence -1/2
@potent dome
potent dome
yh i'm not reading that i'm doing that myself
thanks though
at least someone knows what they're doing
thorny thorn
yh i'm not reading that i'm doing that myself
you do understand how you get the -1/2 tho?