I’m not sure if I did the first part right and need help with second part
#perp bisector
tough hamlet
so ur right abt it being a perpendicular bisector
for the next part those are equations of half lines in the complex plane
convert them to cartesian and find an intersection point
wicked cobalt
Would this be right?
tough hamlet
yes
wicked cobalt
How do I convert them to Cartesian
tough hamlet
well
wicked cobalt
I got it I think
tough hamlet
the argument they give you
is the gradient of the line
so y - 0 = tan(pi/3) (x-2) for first one
wicked cobalt
I don’t understand how I’m suppose to find w
remote gust
Oh dear Argand diagram
wicked cobalt
?
wicked cobalt
Most recent one
remote gust
2023?
wicked cobalt
Yeah
remote gust
Oh could u send me the paper I haven’t seen it before
wicked cobalt
Yeah I will I just need to know how to do part ii
remote gust
Imma do it in a min
wicked cobalt
Like I get that they are 2 half lines but where are they both satisfied
wicked cobalt
Imma do it in a min
Have u done it?
wicked cobalt
No I can’t find the mark scheme
remote gust
Oh man idk if I’m right
wicked cobalt
Can u show me ur working
remote gust
I don’t wanna send my working and then look like an idiot when it’s wrong LOL
This was my thought process
Let W = x +iy then form simultaneous equations
wicked cobalt
Where is ur starting point
wicked cobalt
Let W = x +iy then form simultaneous equations
Is it the stuff on the right
remote gust
Finding arguement is tan-1
And it’s imaginary / real
I don’t wanna tell u this and be wrong best u wait for somebody who knows how to do to do it
remote gust
wicked cobalt
wicked cobalt
There is also this question I don’t know how to do