#where did I go wrong her e
17 messages · Page 1 of 1 (latest)
,rotate
Just find the area of the small one. The sides of the big one must be xp, repeat and take away
Quite simple, let's say the area of a one triangle is 1/2 x (x)^2 x sin60
There are 6 triangles in the small hexagon. Let g(x)=6×Area of one triangle
Since the big hexagon is 6 times bigger by a scale factor of p, let h(x)= 6 x 1/2 x (px)^2 x sin60
then subtract h(x)-g(x) to get that answer.
I use g(x) and h(x) so I don't need to write the equation every time to explain, but you won't need to write it in the exam
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it looks like alot of stuff