#roots of polynomials

31 messages · Page 1 of 1 (latest)

meager heart Apr 22, 2024, 2:54 PM

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lol

edgy pollen Apr 22, 2024, 2:54 PM

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<@&791435371564892232>

edgy pollen Apr 22, 2024, 2:55 PM

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meager heart lol

?

meager heart Apr 22, 2024, 2:55 PM

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which part

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the whole thing
?

edgy pollen Apr 22, 2024, 2:55 PM

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All

meager heart Apr 22, 2024, 2:55 PM

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kl

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so yk -3 + 4i is a root

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what could another root be

edgy pollen Apr 22, 2024, 2:56 PM

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It has to just be an integer

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Cuz there is already a complex conjugate

meager heart Apr 22, 2024, 2:56 PM

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yeah exactly

edgy pollen Apr 22, 2024, 2:56 PM

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-3+4i and -3-4i

meager heart Apr 22, 2024, 2:56 PM

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so the conjugate would be the 2nd root

edgy pollen Apr 22, 2024, 2:56 PM

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Yeah

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But how do I find the third root

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And a and b

high oyster Apr 22, 2024, 2:57 PM

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If u plug both roots you have in you’ll get simultaneous equations

edgy pollen Apr 22, 2024, 2:57 PM

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I got z^2 +6z+25

meager heart Apr 22, 2024, 2:57 PM

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theres different ways

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i would do this

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[z-(-3+4i)][z-(-3-4i)]

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and u get a quadratic

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then you do

edgy pollen Apr 22, 2024, 2:58 PM

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Yeah

edgy pollen Apr 22, 2024, 2:58 PM

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edgy pollen I got z^2 +6z+25

This

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Oh so it’s 7

meager heart Apr 22, 2024, 2:58 PM

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(z-k)(z^2+6z+25) = f(z)

edgy pollen Apr 22, 2024, 2:59 PM

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So third root is 7?

meager heart Apr 22, 2024, 2:59 PM

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then you can compare coefficients

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idk i havent done it