#How do you find the distance between opposite edges of a regular hexagon??????

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wraith bridge
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you can form 2 right angle triangles like so

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you know the line that is not hypotenuse or x is (root3)/2

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since in a regular hexagon the distance of a diagonal between 2 opposite vertices is always double the side length (you can prove this thru cosine rule or basic trig)

wraith bridge
wraith bridge
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no root3 is

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x is half the distance between opposite edges

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diagonal between 2 opposite vertices is not equal to length between 2 opposite edges

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ye

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wait what

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x isnt root3

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AB = 2โˆš3

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PR = โˆš3

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so (AB-PR)/2 is equal to the distance between A and the bit where it intersects with PQ = โˆš3/2

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its a side length

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PA = AQ = PR = RB since its a regular hexagon

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PQ doesnt equal AP + AQ

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np

leaden egret
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Is this correct

wraith bridge
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glad to have helped ๐Ÿ‘

wraith bridge
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no thats correct

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oh i see the ms is wrong here they seem to just have forgotten the square root

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it should be this

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your friend is correct