#How Do you solve (bi) is there a way to always solve these questions the mark scheme doesnt show
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If you notice, the equation in B is the same as a
So if you plug in your R formula from A into it
You’ll get H = 3 + 2(expansion from A)
Where theta = 0.5t
And then to find the max, your cos(0.5t + alpha) will be set to 1
So your max is H= 3 + 2R
Then to find the time at which this occurs
Set cos(0.5t + alpha) = 1 and solve for t
i dont see how it is the same as A
A is 2sintheta - costheta
H = 3 + 4sin0.5t - 2cos0.5t
H = 3 + 2(2sin0.5t - cos0.5t)
Imagine 0.5t = theta
ok i see it now
H = 3 + 2(2sintheta - costheta)
so to solve the max point what do i do now
Alwasy in these trig Qs if they make you solve for the R formula you’ll use it later on
ok
Set your cos(0.5t + alpha) = 1 as that’s the max of a cos graph, so your max is H= 3 + 2R(1)
So 3 + 2R