#Can someone explain this question and how they got to the answer? I'm quite bad at indice rules
48 messages · Page 1 of 1 (latest)
as i thought you'd needed to do 6 - - 2/3 after cube rooted it etc
as thats what the rules state
and how does the -1 get there? wouldn't the 2 - - 2 calculation completely cancel out the indice/
ah this would be true if it was x^6 * x^-2/3
but
$\left(x^{a}\right)^{b} = x^{ab}$
secp256k1
they squared everything first
cube root, simplify fraction inside bracket, square, reciprical
they cubed everything first
so how does it get to y^2 on step 3?
oh right because 1 * -2 isnt it
but wouldnt that make a minus
wdym
2 x -2 = -4
1 x -2 = -2
if you wrote it as $$\left(\left(\frac{2x^2}{y}\right)^{2}\right)^{-1}$$ does that make it easier to see
ok lets just start from the beginning
secp256k1
this is the question
yes
i know that you'd cube root everything first
yes
in thid
you have a power of -2/3
this could explain where -1 came from
the cube root is just a power of 1/3
the -1 represents a reciprocal of the fraction
oh so you just made the 2 positive
ye
but
to the power of -2
just means
flip everything
and raise everything to the power of 2
just break the question in simple steps
yeah i probably should do that
what about these types of qs?
well 4 = 2^2