#Can someone explain this question and how they got to the answer? I'm quite bad at indice rules

48 messages · Page 1 of 1 (latest)

vivid beacon
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as i thought you'd needed to do 6 - - 2/3 after cube rooted it etc

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as thats what the rules state

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and how does the -1 get there? wouldn't the 2 - - 2 calculation completely cancel out the indice/

little robin
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ok

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give me a few mins

drifting warren
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but

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$\left(x^{a}\right)^{b} = x^{ab}$

royal turtleBOT
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secp256k1

little robin
drifting warren
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cube root, simplify fraction inside bracket, square, reciprical

vivid beacon
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they cubed everything first

vivid beacon
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oh right because 1 * -2 isnt it

drifting warren
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yes

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square top and bottom of the fraction

vivid beacon
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but wouldnt that make a minus

drifting warren
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wdym

vivid beacon
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2 x -2 = -4
1 x -2 = -2

drifting warren
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if you wrote it as $$\left(\left(\frac{2x^2}{y}\right)^{2}\right)^{-1}$$ does that make it easier to see

vivid beacon
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ok lets just start from the beginning

royal turtleBOT
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secp256k1

vivid beacon
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this is the question

drifting warren
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yes

vivid beacon
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i know that you'd cube root everything first

drifting warren
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yes

vivid beacon
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then all of that

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but where does the -1 come from

little robin
vivid beacon
drifting warren
little robin
drifting warren
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the cube root is just a power of 1/3

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the -1 represents a reciprocal of the fraction

vivid beacon
little robin
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but

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to the power of -2

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just means

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flip everything

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and raise everything to the power of 2

vivid beacon
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ahhh

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i think my logic is a bit behind ngl

little robin
vivid beacon
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yeah i probably should do that

vivid beacon
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what about these types of qs?

drifting warren
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well 4 = 2^2