#SOCHATOA with graph

37 messages · Page 1 of 1 (latest)

dense cobalt
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Did I get this question correct?

20240329_131842.jpg
lost verge
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22-16=4 for P

dense cobalt
lost verge
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gradient is 2

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every 1 across is 2 up

dense cobalt
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Yes

lost verge
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also its not SOHCAHTOA

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its 2 perpendicular lines meeting each other

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to find the gradient for RQ

dense cobalt
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I see

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How do the two gradients get Q co ordinates

lost verge
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negative reciricol

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i cant spell the word lol

dense cobalt
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Nah hr good

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Y = -1/2x

lost verge
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yh

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then plug that and the coords into the straight line eqn

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coords of R

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to find c

dense cobalt
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What do I put in

lost verge
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y=mx+c

dense cobalt
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What do I put in place of y and x

lost verge
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the coords of point R

dense cobalt
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Ok

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So 22 = -1/2(8)

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+c

lost verge
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then when u get the eqn u set y to 4

dense cobalt
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Why 4

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Sry bro I'm rlly confused

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I got y = -1/2x +26

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Actually bro I understand now

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Thanks for the help

lost verge
velvet saddle
dense cobalt
velvet saddle
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Yh, look at the barcode

dense cobalt