parametric equations

[plain heart]

how would i do part c

i know the identity is sin^2 + cos^2 = 1

but how do i relate that

to the equation of the circle

[icy fjord]

where u even get those from

im coonfused

[brisk cipher]

so you just set x-4 equal to rcost which is 3cost

and the same for y-3

or just draw a triangle

[icy fjord]

oh

[plain heart]

i dont get it

[plain heart]

i dont get why you set the triangle to y-3 and x-4

i understand this would be a unit circle

hence 3 is = radius

so the hypoteneus

[brisk cipher]

because (x - 4)^2 + (y - 3)^2 = 9

so you can use pythagoras

[plain heart]

oh shit

but the links to parametric and everything is driving me crazy

@brisk cipher ive managed to wrap my head around it thank you so much bro

would you know how to do part d?

[brisk cipher]

didn’t see this until 10 mins ago my bad

so y = (24/7)x

since the radius is 3 and the circle is centred 3 units up, the circle is tangent to the x axis, which makes y = 0 another solution

[plain heart]

That makes sense thank you man