#how do i integrate this
35 messages · Page 1 of 1 (latest)
,w 8tanx/(1+sin^2(x))
why 2x
oh my bad
i told you how to do it mate
write sin as tan/sec
and then do u sub as u = tan x
so the sec's cancel out
How did you do it?
omg
ðŸ˜
Just not rated
let u = 1 + sin^2x
do all the simplifying stuff
and you'll end up with sec^2x / u, with 4 outside the integral
we need to get sec^2x in terms of u, and you can do this using the pythag trig identity
u - 1 = sin^2x
(u-1) + cos^2x = 1
cos^2x = 1 - u + 1
cos^2x = 2 - u
reciprocate both sides
sec^2x = 1/2-u
so now we have
1/2-u / u --> 1/(2-u)u
do partial fractions
integrate to get ln's and yeah