#A2 modelling differentials
13 messages · Page 1 of 1 (latest)
Ok surface area of a cylinder, think of a toilet roll and let’s say you “unwrapped it” when you stretch it irs kind of like a rectangle with the diameter as the side length , this is exactly it, 2pir being the diameter and h being the side length, we also have 2 circles to account for so +2pir.^2(2 cirlces) and 2pir (diamter) x h so 2pirh
Just something to think abt until he does the q on his whiteboard
appreciate bro
gives a better insight towards the reasoning behind all this
Yes be warned tho, I forgot to mention one circle is covered by the half sphere so it’s gonna be 2pirh+pir^2