PARAMETRIC???

[wintry tangle]

Please can I get help on part c it’s a mock paper from my school I can’t find anywhere

<@&791435371564892232>

[celest bear]

Just square what you’ve got for y no?

Like both sides

[wintry tangle]

For c I

[celest bear]

You’ll get something on top and then sec^2 t on bottom

[wintry tangle]

i

[celest bear]

Oh

Oh ok

I can show on whiteboard just give me a couple mins

It’s the addition formulae tho

[wintry tangle]

Thank you

No I really tried everything

[celest bear]

I’ll do it

[wintry tangle]

Thank you

[celest bear]

Then part ii

[weak crater]

aaa i just finished it now and was about to send a picture

beat me to it lol

[wintry tangle]

How did you get the red part

[celest bear]

That’s just a fact

[wintry tangle]

You can send yours too haha

[weak crater]

cool

[celest bear]

If sec t is 1/cos t

Then it’s fair to say 1/ sect is cos y

T

[wintry tangle]

Omg yes

Wait

How did you factors out cos t

[wintry tangle]

Factorise

[celest bear]

I just factored out cos t

So cos t divided by cos t becomes 1

And sin t divided by cos t becomes tan t

Which is what you want

Cuz in the show that there’s a bracket w x

Which is tan t

It’s all about looking at what the Q wants you to end at

[weak crater]

ye lol its easier to use the show that bit to guess what to do next

[wintry tangle]

This is crazyyy but it get it now

I would never have thought to do that

Can you also do part b if you don’t mind

😭😭

<@&791435371564892232>

[bitter geode]

3^(x+2) = 9*3^x

so it would be 9 times the integral you found

[wintry tangle]

😭😭

I had the top at 9u and was so stuck

[wintry tangle]

Thank you

Can you do this

Sorry i have no markscgeme and can’t find it anywhere

[bitter geode]

is it just b

i was reading the question by the way my bad

[wintry tangle]

Both😔

[wintry tangle]

It’s ok

[bitter geode]

for a it would be 8

because 2^4 = 16

so a_2n = a_2(4) = a_8

for b you should split it into two sums

[wintry tangle]

I understand a now thanks

But b…

[bitter geode]

split it in two sums

a2 + a4 + … a20 will be:
2^1 + 2^2 + … + 2^10

which is a geometric series

[wintry tangle]

But after a4 would it not be a8

???

[bitter geode]

after a4 it would be a6

a6 = a(2*3) = 2^3

[wintry tangle]

Yhhh haha

😭😭

[wintry tangle]

Is that all?

Is that what it meant by evaluate

[bitter geode]

I’m going to draw it

[wintry tangle]

Thank you

[bitter geode]

the first sum is like that because every odd term in the series is 3 more than the previous odd term

then you’d add the two sums to get the answer

it should be ||2341|| by the way

[wintry tangle]

Oh wait I understand this I’ve been trying to wrap my head around it

I didn’t know there was an answer so I’ll do it when i get home thank you

[bitter geode]

no problem