#binomial expansion
30 messages · Page 1 of 1 (latest)
Have I done the first question right?
And how do I do the second question because I’m pretty sure I got it wrong
,rotate
is it not
$$4^5(1-\frac{3}{4}x^-1)^5$$
Aurora 🪻
and then u find the first using binomial expansion rule
so $$b_n = nx + \frac{n(n-1)}{1*2}x...$$
Aurora 🪻
omg texit is so fun
i forgot the 1+ lol
$$(1+x)^n = 1+ nx + \frac{n(n-1)}{12}x^2 + \frac{n(n-1)(n-2)}{12*3}x^3...$$
Aurora 🪻
I see
My teacher didn’t teach us this rule
I assume it’s in the formula booklet tho
I do ocr mei
I’m sorry to be a pain but could you do a full on solution so I can compare it to what I’ve done
its alr and sure
@atomic lintel give me 5 minutes just wanna try put this all into latex haha i got the paper solution too if u just really need it rn
$$\textbf{Expanding } (4-\frac{3}{x})^5$$
$$\text{Step 1. Make it look nice}$$
$$(4-3x^{-1})^5 $$
$$\text{Step 2. Take the 4 out, so we can get it in the format which our formula uses:} $$
$$ (1+ax)^n $$
$$ 4^5(1-\frac{3}{4}x^{-1})^5$$
$$\text{Again, step 1. Make it look nice}$$ \
Aurora 🪻
Latex wizard