#Quadratics 5 IsaacPhysics, A level Maths Question
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i did and got m(p+b/2m p)^2 - b^2 p^2 / 4m + k = 0
m(p^2+ b/m p) + k = 0
m[(p+b/2m p)^2 - b^2 p^2 / 4m^2] + k = 0
m(p + b/2m p)^2 - (b^2 p^2 / 4m)+ k = 0
do u have the answer btw
I have an answer, idk whether it's correct
But also $p^2 + \frac{b}{m} p = \left( p + \frac{b}{2m} \right) ^2 - \left( \frac{b}{2m} \right) ^2$
Hen