#circle theorem y1 pure
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lines PR and RQ must be perpendicular to each other and both pass through R
PR has equation y-1=m(x+1)
because it passes through (-1,1) and has unknown gradient
which we'll call m
since RQ is perpendicular
it has gradient -1/m
y+5=-(x-7)/m
now we have a system of equations
y-1=m(x+1)
y+5=-(x-7)/m
but there are 3 unknowns
except there actually isn't
because we know it lies on the y axis
so we can let x=0
since that is the definition of the y axis
so we have
y-1=m
y+5=7/m
solve these simultaneously for by eliminating m from the equation
make sure you take the positive solution if there are multiple solutions for y
as the question says the point lies on the positive y axis
you're over complicating it lil bro. It's just (-1,-5)
considering the point lies on the y axis, im not sure how that would work
A point on the y-axis has coordinates (0,k) for some k in 2 dimensions so (-1,-5) doesn't lie on the y-axis lil bro
don't stop your mewing streak next time
I do agree though that it is overcomplicated, if it lies of the y axis then you could just input x as 0 into the equation and take the positive value of y which is 2 so (0,2)
bro what you yapping
I was doing a different question stay humble
what were you working out ๐
It's (0,2) stop yapping
๐๐๐
input x as 0 into what?
which equation
the equation of the circle