#parametrics
17 messages · Page 1 of 1 (latest)
x = cot^2t + 3 y = 3 cost
x-3 = cot^2t y/3 = cost
now you can use one of the pythagoras identities
1 + cot^2 = cosec^2
1 + x-3 = (y/3)^2
then just make that into the form y = f(x)
<@&791435371564892232>
didnt someone just help you ðŸ˜
look at this part @late cove
oh number 2
i haven’t really done parametrics
btw thank you guys
make y=0 and x=0 ad solve
got aired cold
i said "thank you"