anyone help on this q

[outer zephyr]

Oh yeah part b sorry

[dense plover]

You measure them clockwise form north

[chrome chasm]

a) so you got the vectors treat them as coordinates, so use distance formula sqrt(x2-x1)^2+(y2-y1)^2
sqrt(6-2)^2+(-4+1)^2= sqrt(41)

b) its bearing!! 270 + TOA
so 270+tan^-1(1.25)

c) −(2i + j) + 6i − 4j = 4i − 5j
Velocity = 8i − 10j
so λ(8i − 10j) = 4i − 5j
λ = 1
Then you make a conclusion

d) pythagoras
sqrt(8^2+10^2)

e) t=d/s
t=sqrt(41)/part (d)
t= 1/2 an hour.

[worn sigil]

how did you get landa = 1?

[chrome chasm]

they r parallel thts why

[worn sigil]

landa would = 2?

oh wait no

it’ll = 1/2

[fallen kernel]

@outer zephyr all good?