#mat - explain solution
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2015 question 2
screenshot is important fior question and bcs it shows solution to part i)
https://youtu.be/-lCQgLAi7yg?si=FhDANTePBJBWJ24M = solution yt vid
https://www.maths.ox.ac.uk/system/files/attachments/websolutions15_3.pdf = solution doc
https://www.maths.ox.ac.uk/system/files/attachments/test15_1.pdf = question doc (screenshot is sufficient)
mat - why am i wrong
my solution: (read last line for why it is wrong)
||factorised using part i) end up with (3-2)(second bracket)
the second factor (the second bracket) is a geometric series with starting term 3^2015, n=2015 and common ratio 2/3 (bcs you are dividing by 3 and multiply by 2 each subsequenct term)||
||using sum of geometric sequence form, u get the second bracket (the second factor) is the original 3^2015-2^2015
at first i thought this means factors are 1 and itself thus prime
but then ir ealised all numbers can be written as product of 1 and itself - this is not special||
tldr where does this come from
mat - explain solution
Instead of (3-2) (where you let a=3 and b=2) instead let a=3^5 and b=2^5
Ohhh i seee
ohhh so that shows there are 2 integer factors that are not 1 or itself so the number is composite?
Yes
is the second factor determined by just trying numbers and seeing what works?
^
so, its just factorising right? -
part i) only helps bcs it helps with the first bracket idea?
What
No
It’s the same format as the factorised form but you change n