#linear transformations FM
21 messages · Page 1 of 1 (latest)
so theres a matrix for anticlocwise rotations
lemme find it
so u basically equate each part of R to this
and solve for theta
ur gonna get multiple values for theta
when you do the equating and solve for theta you'll see the same angle appear in each of them
thats the angle of rotation
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cos(x) = cos(-x)
I’m still baffled
sin^-1 (1/2) = -30 degrees
cos^-1 (root3/2) = 30 degrees
But cos^-1 (root3/2) also = -30 degrees
Theta = -30 degrees
The rotation is 330 degrees is what solution bank says @silk atlas
yeh which is the same as -30 degrees lol
330 degrees anti clockwise