circles as question

[ancient jackal]

What are u struggling with

[median juniper]

PR is the diameter
Therefore it goes through the centre

Triangles that form a semi circle have a 90° opposite the diameter

The diameter is also the hypotenuse, therefore.

Since it's a right angle triangle you use Pythagoras theorem to workout the lengths PQ and QR

Then using these lengths you use Pythagoras theorem once more to find the length PR

Now create a point S at (a, 2)

Join the points PS and SR to create a triangle

Length SR is 2
Find PS using Pythagoras theorem

Add the value for PS to -3, you should get 13

||I think this is correct, hopefully I didn't overcomplicate it||

[pure mantle]

ohhh that makes sense tysm