is it possible to integrate this to (1/k)(ln kx) ?
#integration
past tangle
fringe roost
Integrates to ln(x)/k
Take 1/k out of the integral and you’re left with the integral of 1/x which is ln(x) then multiply by the factored out 1/k
past tangle
but if i dont take 1/k out i can still integrate it to ln(kx) (1/k)
because try differentiate it
you get the same thing?
past tangle
Wanna see how?
no i done it bro, but the thing is it can also integrate to ln(x)/k
idk how thats possible
wide chasm
K is a constant
It can also integrate to lnk^2x/k
U can keep going substitutions and increasing the size of the power of k
past tangle
does that mean, when i put the limits in with the different integrals, ill get different answers?
cos i put them in and got different
wide chasm
Look
The more substitutions u make the more u can increase the power of k if u wanted to
,rotate
astral cliffBOT
past tangle
where did u get du/dx= k from?
wide chasm
Substitution for u = kx
past tangle
and i was talking about these limits bro
past tangle
ok
wide chasm
I’m assuming you did it by substitution
astral cliffBOT
wide chasm
U see how u get k squared
past tangle
wide chasm
Ok sweet
Now u can get that rule by using substitution
When u use substitution
The limits change
past tangle
U see how u get k squared
yup
past tangle
My bad if it looks complicated
nah its good i appreciate the time
past tangle
that makes sense i didnt change the limits
wide chasm
is there a video on yt about that?
search up integration by substitution to maths teaches it quite well in my opinion
past tangle
tl maths?
wide chasm
Yeah
past tangle
alright thank you mate
wide chasm
No worries bro