A2 trig

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can someone do e please

[proud saddle]

Break down the cubed ones so that you can get a sinθcosθ then turn it into sin2θ

2(1/2 sin(2θ)sin^2(θ) +1/2 sin(2θ)cos^2(θ))

Now factor out sin2θ and the halves will cancel out with the 2 you'll be left with sin2θ and sin^2+cos^2 which is 1

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got it thanks

[proud saddle]

Nws

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could you help with i as well please ?

[proud saddle]

So first use addition rule for tan

You'll have a fraction then you should multiply the numerator and denominator by cosx

Now you're supposed to have cosx–sinx/cosx+sinx

Now multiply the numerator and denominator by cosx–sinx

You'll have the identity for cos2x in the denominator and when you expand the numerator You'll get the identity for sin2x and sin^2+cos^2

This question is a bit long tbf

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i dont get how to simply it to cox-sinx / cosx+sinx