Can someone tell me step by step I wasnt taught this

[desert condor]

Work out the value of 2^x = 64^1/2

Is it?

[nocturne hollow]

Can rewrite 64 as 2^6
So 2^x = (2^6)^1/2
2^x = 2^6/2
x = 3

[desert condor]

Tysm

[desert condor]

How would I do 4^x = 32^1/5? Sorry if Im asking too much questions

[modern silo]

32^1/5 is the 5th root of 2

so 4^x = 2

2 is root 4

so x is 1/2

[nocturne hollow]

rewrite 4^x as (2^2)^x
rewrite 32^1/5 as (2^5)^1/5
2^2x = (2^5)^1/5
2^2x=2^1
2x=1
x=1/2

[nocturne hollow]

Or that

[desert condor]

Alright 🙏