Complex Numbers (loci) A level further maths

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which part

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All

I drew a diagram for 1

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alright

yh so

the first one

both of them are a circle

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I know that 2 is to do with perpendicular bisectors

Yeah

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yh 2 i sperpendicular bisectors

first one

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Do we need to work out the intersection point for one

Question 1

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whats the centre for both equations?

for first one

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nah i dont think so

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(-2,2) and (2,2)

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yh beautiful

and u got the radius

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Yeah

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the first one everything inside the circle is shaded right?

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2root2

Wait lemme show you

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and second one everything outside is shaded

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yh looks about right

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"Not to scale"

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yh ofc

yh im pretty sure thats right

u havent coloured any part of the second circle right?

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But the question says set of points whicjh i dont understnd

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even the overlap

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Nope

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yh thats calm

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ah

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Normally it would say shade if it wants us to shade you get me?

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yh i think

it means just shade the area

coz idk how u would find thr set of point ngl

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Alright cool

I though maybe it would have do with inequalities and all

But its ok

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i doubt it

might be but i dont think os

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Any help on the 2nd question?

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so

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Its fine

Ill leave it as that

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yh thats a new question to me

but what i would do

is find the equation of the line

in cartesian form

for the perpendicular bisector

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x=-1

If you ignore the 3

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yhh

ah yh

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But that three is giving me a headache

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so

yh ive never encountered smt like that

but

i think

u would convert it back to complex form

so its essentially a half line

i think

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True

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ac is it?

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With a mod of 3?

From the origin

?

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i dont think u can say its a half line ac

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why this?

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its a straight vertical line with no start or end

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I though maybe the three might indicate the modulus so the line has a length three from the origin but very unlikely to be true

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I know but the three is making me think otherwise

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i dont think thats what the 3 is ngl

u might be right but

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Ive tried searching online but no ise

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idk

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*use

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maybe

maybe

treat the right hand side separately

so its like an equation of a circle

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Ohhhh

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then take into account the left hand side

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Centre (-1,0) radius 3

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sorry i meant right hanf side

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nah i meant right hand side my bad

so -3,0 and radius

3

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I dont understand

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treat the right hand side first

ignore the modulus z-1

so when u have

modulus z+3 = 3

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Right...

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its becomes an equation of a circle

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Yeah

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which would have a centre -3,0

and radius 3

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Correct

Then where does the left hand side come in

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but then idk how we would plug the modulus z-1 back into that

😂

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😭

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yh idk bro

im sorry

couldnt help u

ask a maths mentor or smt

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Hmm

I feel like its a simple question

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yh sane

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But im overthinking

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idk if im just tripping

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Well its fine

Thanks for the help anyways

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i apologise bro

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didnt help

ping a maths mentor

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Do you want me to share the solution once i get the answers if i dont get it from this server, like from sch or somethin?

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yes plz

ping me on this thread

ill respond whenever im on here

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<@&791435371564892232>

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yo maybe u can treat the right hand side

draw the circle

then draw the perpendicular bisector

afterwards

so uno the equation of the circle

-3,0 radius 3

and the perpendicular bisector is x=-1

which intersects the circle

if ygm

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Sure?

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idk if thats the right way but just another thought

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I appreciate it

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Question 1:

Question 2:

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ahh