#trig modelling

50 messages · Page 1 of 1 (latest)

safe flare
#

part d

Screenshot_2023-11-08_at_13.15.06.png
safe flare
#

Asking cuz again help d) 😭😭😭

safe flare
#

Hello again

dull elm
#

part d

#

right

safe flare
#

Yea

#

D

dull elm
#

you'd set H to 0 first

safe flare
#

Cuz it like saying it came back to its position

dull elm
#

yeah

safe flare
#

But it does that twice so u look at the 2nd solution ?

dull elm
#

i think it would be the third solution

#

the first solution should be when the wheel hasn't moved anywhere

safe flare
safe flare
#

They just said

#

Pi t /5 =2 pi

dull elm
#

hm

safe flare
#

I think it's something to do with stretches in x

dull elm
#

the problem is

#

2 pi is a full revolution around a circle

safe flare
dull elm
#

so you'd think they'd look for 4 pi

safe flare
dull elm
#

since that would be two revolutions

#

but

#

if you think about it

safe flare
#

Ooh yea sorry I meant 4 pi above not 2 pi

dull elm
#

ohhh ok lol that makes more sense then

#

yeah they set it equal to 4 pi because 4 pi is 2 revolutions

#

if you look at a cos graph it makes a bit more sense

#

because in its 2 pi cycle it only hits the minimum point once

#

actually no

#

because it's -Rcos(x+a) and not +Rcos(x+a)

#

we're interested in the maximum value of the cos function since that's when the height will be at its lowest

#

and again looking at the graph you can see it maximises every 2pi starting from 0

#

and we want it to maximise twice so 4pi is what we're looking for

#

so we find the t value that makes the input of the trig function 4pi

safe flare
safe flare
#

It has nothing to do wd question right

dull elm
#

in order for a revolution to be completed the passenger must end up at this lowest point again

safe flare
dull elm
#

because a full revolution is 2pi the function must have cycled through 4pi to complete two revolutions

#

even ignoring the context of the question