reciprocal graphs

[mint brook]

im confused on how to approach part a

[fallow juniper]

you're dividing by a greater number

so the graph will shift left a little bit

and the asymptote will be at a different place, you can find out the y intersection just as normal

[mint brook]

how would i find the y intercept

is it just 3/2

[fallow juniper]

x=0 so yeh

[mint brook]

ah ok