#please
57 messages · Page 1 of 1 (latest)
nah separate the brackets
do 2(x+4) first
which is 2x+8 right?
then do 3(2x-1)
basically what i did was expand the 3(2x-1) as if it was to be positive
and then i changed it to negative by switching the signs
6x would then be -6x
-3 would then be 3
2x + 6
what about 3(2x-5)?
yup @limber oxide