Help

[real bear]

Help pls for a)

[loud glacier]

Use the discriminant

[real bear]

yh

[loud glacier]

Equate the two equations then b^2–4ac<0

Show me your working

[real bear]

1 sec

Also need help with this

I am working out the 1 Above

gimme 5 mins

[loud glacier]

Make all the bases 3

[real bear]

@loud glacier

Then what do u do for the initial question

[loud glacier]

Your c is wrong

It's 4p+7

And you should put the b that way in your equation in step 2 (–6p–3)x

Cause –6p–3 is the coefficient of x

@real bear

[real bear]

ohhh

then what do I do?

[loud glacier]

Just like you did

But fix your values

And since the line and the curve don't intersect or touch then b^2–4ac<0

[real bear]

OHH

Tysm