modulus problems Alevel

[severe river]

how does one do this question?

[true depot]

for range, find the minimum point

and its above that value

to find midpoint, 2-x=x-2, x = 2

plug in 2 into equation to find value, and range is

y> that value

[severe river]

so

f(x) is greater or equal to 4?

[true depot]

yes

[severe river]

how do u do next one?

[true depot]

and then for b

[severe river]

mhm

[true depot]

oh x >= 0

so it would intersect when gradient is positive

[severe river]

so what would i do about it?

[true depot]

so 3(x-2)+4 = x+20

[true depot]

you choose x-2 and not 2-x, because graident is positive

[severe river]

OHHHH

i just worked it out so x=11?

[true depot]

and then for c

leme read it

[severe river]

oki

[true depot]

yep

[severe river]

tysmmmm

how do u do c?

[true depot]

well for c

if you sketch it out

its when k is above the minumum point of f(x)

wait isnt c just the same as a

[severe river]

uhhh i think?

im not sure

i think it involves

[true depot]

it should be if im not wrong

[severe river]

the like < thingy

[true depot]

yeah so k>4

not >= because equal means theres 1 root

so its k>4

[severe river]

yhhh

alright okkk

doesnt it say 2 roots tho

[true depot]

yeah which is why its k>4 not k=>4

[severe river]

the answer is saying 4<k<or equal to 10

[true depot]

oh shit i forgot x>0

my bad

[severe river]

nah its fine 😭

[true depot]

wait so you understand why its 10 right

[severe river]

no not rlly

[true depot]

oh

its between these ranges

cuz above the y intersection, there would only be 1 solution

so you need to find the y intercept of f(x) and that is ur maximum value

[severe river]

ahhhh i see

[true depot]

its <= rather than < cuz at 10 there are 2 roots

[severe river]

yh that makes sense

tysm :)))