a level maths functions question

[junior hamlet]

Can someone help

Q 7 8

[autumn zinc]

that is unreadable

ill try tho

domain: x=>5

[junior hamlet]

This is clear pic

[autumn zinc]

cuz ln(x-4) = 0, x-4 = 1, x = 5

[junior hamlet]

How do u do it

Why is it equal to 1

X-4

[autumn zinc]

cuz e^0 = 1

[junior hamlet]

oh

[autumn zinc]

cuz im making both sides e^

[junior hamlet]

Okay

U r both sides

Yh make sense

[autumn zinc]

wait what does it mean by largest possible domain

[junior hamlet]

The answe is x>= 5

[autumn zinc]

oh ok so it just means domain

[junior hamlet]

I think u just have to put the greater then equal to inequality

Yh Yh

[autumn zinc]

then for 8

[junior hamlet]

I wasn’t in skl for this topic so I’m struggling

[autumn zinc]

u merge the fractions into 1

and make the denominator = 0

[junior hamlet]

Yh

[autumn zinc]

and find what values of x is not 0

[junior hamlet]

Ok

Can u try the tohers if u have time

Like what to do

[autumn zinc]

oh and x should also be greater than >=1

[autumn zinc]

kk

[junior hamlet]

Yh that right I checked

[autumn zinc]

this is cuz of the power

[junior hamlet]

how can I learn functions Myslef I was away and missed lessons

[autumn zinc]

root cannot be negative

[autumn zinc]

look thru the book, understand concept through videos and just do practice questions

thats about it really

[junior hamlet]

Alright

[autumn zinc]

im kinda busy sry can u tell me speicifc questions u cant do

[junior hamlet]

I have 10 11 and 12 left

Is 10 the same concept as 7

[autumn zinc]

yep

the thing inside ln cannot be negative

[autumn zinc]

ok eme look at it

[autumn zinc]

for 11, denomnator cannot be 0, and the thing inside the root cannot be negative

[junior hamlet]

Ok thanks

Also@

[autumn zinc]

np

[autumn zinc]

12, the root and ln cannot be less than 0, so just work around that

[autumn zinc]

i think one one means that there are never 2 same values of x or y

[junior hamlet]

Okay thanks a lot bro

[hollow blaze]

Won't the transformation just shift the asymptote of x=0 4 units to the right so the asymptote will be at x=4 now hence domain is x>4 ?

It will intersection the x axis at 5 but ye that doesn't mean anything bout the domain tho ?

[autumn zinc]

ln0 = undefined

lnx where x<1, is negative

u cannot have a root of a negative number

so root(ln(x))

[hollow blaze]

Yea ik thats y I said asymptote

[autumn zinc]

the domain starts at x=1

[hollow blaze]

I don't get what u r trying to say

[autumn zinc]

since its x-4, it shifts by 4 to the right so domain starts at 5

[autumn zinc]

okay leme open desmos

[hollow blaze]

Alight sure

[autumn zinc]

so here, its root(ln(x))

[hollow blaze]

Yep

[autumn zinc]

it starts at 1 because, if x was less than 1, lnx would be negative right?

[hollow blaze]

I see

[autumn zinc]

such as ln0.5 = -2 i think

[hollow blaze]

Yea yea

[autumn zinc]

wait no it doesnt im stupid

but whatever ln0.5<0

[hollow blaze]

😭😭what ?

[autumn zinc]

ignore that LOL

my brain didnt work for a sec

[hollow blaze]

Yea log of any number less than 1 is negative

[autumn zinc]

mhm

[hollow blaze]

Also I was wondering if the base is less than 1 does that also make it negative ?

[hollow blaze]

Yea

[autumn zinc]

uhhh i think so

leme check

wait no

no it doesnt

log,2 base 0.5 is positivre

[autumn zinc]

=4

[hollow blaze]

Let me just bring up the question again lol

[autumn zinc]

oh wait ur the same guy as kyz?

nvm

[hollow blaze]

Wdym same guy ?😭😭

[autumn zinc]

BRO MY BRAIN IS NOT HERE

[hollow blaze]

Nah fr

[autumn zinc]

ok ignore me again

[hollow blaze]

Okay so

Ln(x-4) has to be positive

To do that x-4 must be greater than 1

Cuz log off any number less than 1 would make it a fraction ahh I see nvm

[autumn zinc]

yep

[hollow blaze]

Thx alot tho

[autumn zinc]

np!

sry i was a bit doodoo here and there

i just came back from school thas why

my brain a lil fried

[hollow blaze]

Lol all good