quadratics as

[devout reef]

find the discriminant

yeah but hold on

checking something

nah

lol

[marsh jetty]

Yea

[devout reef]

I don't 😭

physicsandmathstutor

just do practice qsa

after every topic

and you'll be good

[mystic wedge]

u in uni )

ah was gonna

all good

[devout reef]

but yeah just find the discriminant and put it in the form

np

u should've gotten two roots

idk

haven't done it

check it on ur

calculator

wait

nvm

I forgot how to do this topic

[mystic wedge]

it is 16

[devout reef]

lemme do the question real quick

oh

[mystic wedge]

right?

[devout reef]

IDK

u tell me

[mystic wedge]

u tell me

[devout reef]

..

bro

[mystic wedge]

ur name is litro tech

[devout reef]

💀

[mystic wedge]

your level 20 compass 💪💪

[devout reef]

real

are u sure it's just 16?

yeah

I'll do the q in a sec

alr lemme do it

how'd u get 16?

x1 = 1, x2 = -3

yeah

can u send ur working rw

rq

wanna compare it to mine

???

wait

.

I messed up the question sigh

ah yeah

k = plus or minus 16

k = 16

yhh

it throws u off a lot

I'll be real I haven't done this topic in 3 weeks

I'm 50/50

uhh

<@&791435371564892232>

[quiet summit]

whats the question

[devout reef]

@mystic wedge

[lime pollen]

,rotate

[rapid plover]

Discriminant is more than or 0

[devout reef]

there's no or equals

wait

[rapid plover]

Hence (k-3)^2- 4*(3-2k)

[rapid plover]

Didnt mean or equals

[rapid plover]

Just a typing mistake

[devout reef]

what's the question asking

[lime pollen]

this

[devout reef]

mums

[devout reef]

isn't it k=16

[devout reef]

I done this originally

[lime pollen]

Bro it's justy telling you to show that k satisfies the equation

[devout reef]

but u were just proving it was the original quadratic

[lime pollen]

We don't have any other questions 😭

[devout reef]

so u solve for k?

[rapid plover]

Yeah sure but u don’t have to

[lime pollen]

If you wanna semd the full thing then send the full thing but thats the question I got so Im answering how to do that

[rapid plover]

Satisfies just means fits in

[lime pollen]

cool so why are we trying to find what k is

[devout reef]

yes

[rapid plover]

U prove it fits in because the discriminant is a fact

[devout reef]

so u solve for k

[rapid plover]

And so is the quadratic

[devout reef]

to prove its > 0

[rapid plover]

Do you mean substitute k back into the discriminant

[devout reef]

wot

[devout reef]

no

why would u do that

[rapid plover]

What’s more than 0 then

H said to prove it’s more than 0

U

What’s gonna be more than 0

No it’s not just need to understand what the questions asking for

Yeah

[devout reef]

k

..

[rapid plover]

But it isn’t

K can take -3 and 1

-3 is less than 0??

[lime pollen]

"Show that k satisfies k^2 + 2k - 3" That's what it wants

yes

[devout reef]

ahhhh

so that's why

[rapid plover]

Nah bro not at all

[lime pollen]

ah rigght

[devout reef]

when I inputted it in my calculator

I got those but was mad confused

[lime pollen]

yeah you don't need to think about the actual wording of it. Normally if it says "Show that" then gives you an equation, you're using the first equation and turning it into the second
They use "satisfies" because you're showing that for a value of k that makes k^2 + 2k - 3 > 0 true, the equation with xs will always have 2 distinct roots, and obviously when it doesn't satisfy that then it won't have 2 distinct roots

[rapid plover]

Not to over complicate things but u have 2 facts:
X^2 + (k-3)x + (3-2k)
And
B^2 -4ac > 0

The question is asking you if you can take the value of k from that first equation and put it in a format that looks the same as the (k^2 -2k -3 > 0)

And we can using our second fact of the discriminant

[devout reef]

ahh

alrigjt

do u have to show the roots

[lime pollen]

to saay that k satisfies that inequality is to say that any value of k that makes the inequality true will give the outcome you want (the equation has 2 distinct real roots) and any value of k that makes it false will give the outcome you don't want (the equation doesn't have 2 distinct real roots, either 1 or 0 reak roots)

for part a you don't

[devout reef]

or just show that equation 1 = equation 2

alr tysm