#Partial Fractions
12 messages · Page 1 of 1 (latest)
u don't
$$\frac{4w}{1 - w^4} = \frac{4w}{(1 + w)(1 - w)(1 + w^2)}$$
AmbivalentChamp
Hence
$$\frac{4w}{(1 + w)(1 - w)(1 + w^2)} \equiv \frac{A}{(1 + w)} + \frac{B}{(1 - w)} + \frac{Cx + D}{(1 + w^2)}$$
AmbivalentChamp
1 + w² isn't real so the fraction has to have a linear numerator