#idk where I went wrong
22 messages · Page 1 of 1 (latest)
<@&791435371564892232>
well the volume of water in both shapes will be the same
so u can equate the volume of the hemisphere to the volume of the cone and solve for r
I did. that
u made a mistake in ur first line
u worked out the volume of a sphere then multipled by 2/5, not a hemisphere
also instead of doing an underscore for the unknown radius, just write r
it'll make it much clear
Yea I was bugging out in the moment, r my steps still correct tho
Jus so I know im on the right track
yh seems like it
Wait yk Ur volume of cone with water step I kinda don’t get it
Why is it =4pi r squared
cos that's the volume of cone with the water filled
1/3 x 12 is 4
and then there's pir^2 left
Phhh okkkk