how would i sketch f. so far ive found out the roots are just 1 and the y intercept is just 1. it doesnt work if i draw the graph though because it will intersect in the negative side of the x axis, even though there shouldnt be a second root
#sketching cubic graphs help
wanton fiber
Shouldnt X=0 also be a root
stark pawn
X=0 is also a root
stark pawn
Shouldnt X=0 also be a root
Yeah exactly
wanton fiber
And X=1 is a repeated root, so the curve touches it, then goes back without crossing it
And y intercept is 0 I swear
stark pawn
And y intercept is 0 I swear
yeah I think it is
wanton fiber
So it goes up through the origin, then curves down and touches (1, 0), then curves back up without crossing the X axis
granite ingot
Hi
oh okayyy thank you
yh i was seeing pics on google intersecting thru the origin i see why now
wanton fiber
Idk how in depth it wants it - if it also wants you to label turning points, you need to use differentiation, idk whether the question wants that too
granite ingot
oh no they said not to worry abt turning points for now
wanton fiber
yh i was seeing pics on google intersecting thru the origin i see why now
If you are really stuck on a graph and want to see it drawn, use a tool called "desmos"
wanton fiber
oh no they said not to worry abt turning points for now
Yea, that's later on when you study differentiation
granite ingot
oh yea desmos graph ty i’ll do that next time
whered u get the y intercept from tjo
wanton fiber
The independent term (i.e. the thing that doesn't have an X)
Think about it this way - at the y intercept, X = 0, so if you substitute 0 into X, then all of the X cubed, X squared, X on its own, etc. Go away and you're left with y = _, and that _ is the y intercept
So here there's no independent term, and you get y = 0
If it were ((x-1)^2)X + 5, then the y intercept is (0, 5)