straight line

[sturdy orchid]

How do i find A? These Qs put me off

A and B are the points (a. -5) and (2. -8) respectively. AB is parallel to the line with equation 5y-3x=10

Determine the value of A

[bright blade]

If they’re parallel what does that tell you about the gradients

[sturdy orchid]

There equal?

[bright blade]

Yep

So you need to find the gradient of AB in terms of a and then equate it with the gradient of that line

[sturdy orchid]

Whats the gradient of the other line

3?

[sturdy orchid]

.

Didnt reply by accident

[shrewd void]

both gradients are the same so -3

then sub b into straight line formula

[sturdy orchid]

Wouldnt it be 3 if u make it y=

[shrewd void]

yh your right

[sturdy orchid]

Im confused now

Wheres b

[shrewd void]

the coordinates of b

2,-8

[sturdy orchid]

Oh right

[shrewd void]

have you seen the equation y1-y=m(x-x1) yet

[sturdy orchid]

No

[bright blade]

It’s not 3

[sturdy orchid]

How

[bright blade]

Rearrange for y

[shrewd void]

you’d have to make it y not 5y

[bright blade]

Ye

[sturdy orchid]

So 3/5 x + 2?

Y=

[bright blade]

Yep so your gradient is

[sturdy orchid]

3/5

[bright blade]

Ye

Now equate that to the expression for the gradient of AB

[sturdy orchid]

Then do gradient of AB= 3/5?

And solve for A?

[bright blade]

Ye

[sturdy orchid]

Thank you