Logarithms Ch14

[topaz iris]

You need to rewrite both sides of the equation in terms of log5

[scenic salmon]

log5x^2 = 1 + log56

i got to that bit

but idk what to do after that

i tried getting all to one side making it equal to 0 but idrk what to do next

[topaz iris]

minus log5 6

[scenic salmon]

what about the 1?

[topaz iris]

let it equal to one

[scenic salmon]

oh i was thinking it was some quadratic stuff

ok wait lemme do that

eh?>

i got x^2/6 =1 @topaz iris

then

[topaz iris]

keep the log on the LHS

[scenic salmon]

?

like

laws of logs

[topaz iris]

Log5(x^2/6)=1

[scenic salmon]

i divided

but

even then

1 to the power of 5

is just 1

so you get x^2/6=1

[topaz iris]

Other way round

it's 5^1

[hardy sequoia]

Its 5 to the power of 1

[scenic salmon]

Oh sugar

mb

got it root 30 right

[topaz iris]

yeah

[topaz iris]

I usually remember it using log10(100) = 2

[scenic salmon]

i normally remember that the small number is the base so is the bigger one but on this occasion that left my head

you know the other one

do i gotta expand brackets

for both sides

@topaz iris

[topaz iris]

For the 2nd q?

[scenic salmon]

yeah

[topaz iris]

DId you get log9 (x+1)^2 = log9 (2x-3)^2 + 1?

[scenic salmon]

yup

but do i gotta expand those

[topaz iris]

Yeah

[scenic salmon]

damn0

damn-*

then what...

thats a whole lotta stuff

[topaz iris]

Where you up to

[scenic salmon]

ok so

log9 x^2+2x+1=log9 4x^2-12x+9 + 1

that

[topaz iris]

Since you have the same log base you can just equate it

[scenic salmon]

i can do what

what that mena

mean

[topaz iris]

So you can just get rid of the log 9

[scenic salmon]

wait why

since when

what

they just cancel

[final idol]

You can answer this q the same way you answered the previous one

[scenic salmon]

the last one was a whole lot simplet

[final idol]

So log9 ((x+1)^2 / (2x-3)^2 ) = 1

[scenic salmon]

i didnt know you could cancel out the logs

but ig thats just standard

wait what im still stuck @final idol

im kinda lost

[final idol]

Yeah the log rule logm(a)=logm(b) means a=b

[final idol]

Go with this method

[scenic salmon]

how do you divide by that tho

[final idol]

Forget about the division for now

How do you get rid of the log on the LHS

[scenic salmon]

but then what do i do then

[scenic salmon]

?

[final idol]

You got log5 (x^2/6) = 1 for the prev q right

How did you get rid of the log 5

[scenic salmon]

OHH

SHI MB

9 to the power of 1

9

[final idol]

Exactly

[scenic salmon]

then

times the bottom

out

[final idol]

Yep

[scenic salmon]

then solve?

omds ma

so simple

[final idol]

You’ll get two solutions

[scenic salmon]

i did this so wrong 💀

after doing everything i got to 35x^2-110x-80 @final idol wth did i do

[scenic salmon]

=0

equals 0

i didnt solve yet

but that seems wrong

[final idol]

Divide by 5

[final idol]

Also should be +80

[scenic salmon]

you are correct mb once again

ok it works ty

[final idol]

Np

[scenic salmon]

wait @final idol

even tho you get two solutions

how come the answer is only one

not like that i dont get 2 solutions im saying

like whys there only one answer to this

[topaz iris]

What are ur two solutions

[scenic salmon]

2 and 8/7

[final idol]

Try subbing 8/7 into 2log9(2x-3)+1

[final idol]

Now looking at it there was an easier way since we had (x+1)^2 / (2x-3)^2 = 9

That’s the same as (x+1/2x-3)^2 = 9