#partial fractions
3 messages · Page 1 of 1 (latest)
well A/(x-1) + B/(x-1) = something/(x-1) + something/(x-1) = (something else)/(x-1)
3 messages · Page 1 of 1 (latest)
as in, why can't we express the right hand sign fraction as A/(x-1) + B/(x-1) + C/(x-2) instead?
<@&791435371564892232>
well A/(x-1) + B/(x-1) = something/(x-1) + something/(x-1) = (something else)/(x-1)