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[hexed hazel]

Why are you doing that

$\tan(60) = m \therefore y - 0 = m(x + 2)$

[candid ember]

clarence

[maiden pond]

no clue what that is, looking through the maths channels ive seen that in Scotland we are taught differently but anyway i know to get to that point, its expanding into the y = mx + c that im a bit stuck on

[hexed hazel]

Point slope form

It does the same thing as y =mx + c but it allows you to work more things out

[hexed hazel]

Well the gradient is tan(60)

[maiden pond]

oh right, never seen that one before

[hexed hazel]

$y -y_1 = m(x-x_1)$

[candid ember]

clarence

[maiden pond]

yeah no i get that, but if ur just leaving m = tan60 and subbing in it into m in the form, what would u get for the answer?

[hexed hazel]

$y = \sqrt{3}x + 2$

[candid ember]

clarence

[maiden pond]

oh that simple, lol thought it would be different from that. thanks

[pulsar spear]

why was the post deleted

i wanna see the q