2y-x(x-1) - 3(x-3)² y-2
------------------ = --------
(x-3)²(x-1) 2(4-x³)
#rearranging equation
limber parrot
That'd be my first bit...
Then I'd probably give up 💀
You'd cross multiply..
This is long..
limber parrot
My brain is dead after GCSEs
limber parrot
im getting stuck after tho
Same
novel hare
i dont wanna expand and get powers of 4 and higher
after u move all the ys to one side
red plaza
Step 1: get everything with y's on one side
limber parrot
2y-x ~(x-1) ~ -3~(x-3)²~ •2(4x-x³)=y-2 ~(x-3)²~ ~(x-1)~
(2y-x)•2=y-2
How do you do the strikethrough
novel hare
You cancel down
what do u cancel
limber parrot
See the things with ~
Between every 2
Those get cancelled
I might have broke maths rules tho
I forgot but this makes sense..
novel hare
2y-x ~(x-1) ~ -3~(x-3)²~ •2(4x-x³)=y-2 ~(x-3)²~ ~(x-1)~
(2y-x)•2=y-2
i dont understand this
novel hare
Step 1: get everything with y's on one side
ok
limber parrot
Basically there's a (x-1) on both sides
So you cancel them out
There's also a (x+3)² on both sides
Cancel those out as well
novel hare
i dont think u can cancel out like that tho
limber parrot
Yeah I was debating that