NEED SOME HELP

[wooden meadow]

<@&791435371564892232>

<@&791435371564892232>

[timid elbow]

You know that when it’s at a maximum, V= 0

Use S = ut + 1/2 at2

It’s a quadratic

Just put V = 24.5

[wooden meadow]

is that for part a)

[timid elbow]

First part js I didn’t see it

[wooden meadow]

can u check i got 98m for part a)

[timid elbow]

Yeah it’s right

[wooden meadow]

how about part b) mainly stuck there

[timid elbow]

The second part I feel you should draw a diagram

Basically find out t when v = 24.5

[wooden meadow]

what one should i not use s=98 u =39.2 v=24.5 a=-9.8 T=?

what equation i use

[timid elbow]

The total time to get the the original height is 8

[wooden meadow]

but doesnt it start at 39.4 so wouldnt it look like a neg quadratic ?

[timid elbow]

To get that u just use s = ut + 1/2 at2

[timid elbow]

It’s projectile

[wooden meadow]

is my u value 24.5

[timid elbow]

No

[wooden meadow]

so how i use this

[timid elbow]

So you see my diagram

[wooden meadow]

yh

[timid elbow]

Where s = 0 is what you wanna find

So treat it as a queadrstic

S = ut + 1/2 at2

And you get 8

V = u + at is used to find when v is first 24.5

[wooden meadow]

@timid elbow

so thats the time where it first hits 24.5

?

[timid elbow]

Yeah

It’s 1.5

I made a mistake

And here’s the thing

With projectiles

[wooden meadow]

negative 24.5 then?

[timid elbow]

No

[wooden meadow]

oh ok

[timid elbow]

And do the same to find it for the second half

The thing about projectiles is that there’s symmetry

The time forward is the same as the time backwards

[wooden meadow]

would there be symmetry if being thrown off 98 m to ground tho

[timid elbow]

The 98 doesn’t matter because from then on it’s gonna be larger than 24.5

[wooden meadow]

oh yhhh

u right

[timid elbow]

So what we wanna find is the time it’s less than 24.5

So we do 8 - 3

And that gives 5

[wooden meadow]

wait im lost

where we get 8 from??

[timid elbow]

So assume that the origin is the base

[wooden meadow]

yh

[timid elbow]

Like it’s not on top of a cliff

[wooden meadow]

ok

[timid elbow]

And with that the projectile will have the same speed initially and the same speed final

By this I mean that when s = 0 where the particle is at s = 0, the velocity are the same

That sounds confusing

[wooden meadow]

ok

[timid elbow]

Basically 1.5 forward will give 24.5 and 1.5 seconds from t

So we wanna find the time in the middle

[wooden meadow]

so answer is 7 ?

[timid elbow]

No

[wooden meadow]

fuck

😂

[timid elbow]

Because the total time of that motion is 8

[wooden meadow]

the total is 10 second tho

[timid elbow]

We don’t include the part below 0

[wooden meadow]

oh

[timid elbow]

We assume that there’s no cliff

Cause that part don’t matter

[wooden meadow]

ok how did we get 8 tho

like by what equation or

[timid elbow]

You know when t = 8, the velocity is the initial velocity

S = ut + 1/2 at2

It’s a quadratic

[wooden meadow]

yh what we sub in

[timid elbow]

Where s = 0

[wooden meadow]

ok

[timid elbow]

T is unknown

U is the 39

0.5 a is 0.5 x -9.8

[wooden meadow]

(0)=39.2(t)+1/2(-9.8)t^2

[timid elbow]

Yeah

And when you sub it in you’ll get t = 0 and T = 8

[wooden meadow]

ohhhhhh i get it so u kinda just like rise the floor level to the cliff

and replace ur T

[timid elbow]

Yeah

[wooden meadow]

damn that smart asl

[timid elbow]

U can do it where the s is always raised above

But that just makes it harder to understand

[wooden meadow]

ok so answer should be 5

[timid elbow]

Yeah

[wooden meadow]

thanks a lot if u have some spare time can u look at my other post its the car and trailer one

[timid elbow]

Try it this way

So now the y intercept will be 98

[wooden meadow]

sorry had to go do something

ok will do now

[wooden meadow]

no real root

[timid elbow]

See it as a quadratic

Basically the quadratic equation is now -4.9t^2 + 39.2t + 98

And if you make it s= 0 then you’ll find the time it takes to hit the ground

[wooden meadow]

yh u right